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2 years ago

Which of these equations have no solution? Check all that apply.

Mathematics

2 answers:

worty [1.4K]2 years ago

7 0

Answer:

a.) 2(x + 2) + 2 = 2(x + 3) + 1

b.) 2x + 3(x + 5) = 5(x – 3)

e.) 5(x + 4) – x = 4(x + 5) – 1

Step-by-step explanation:

a.) 2(x + 2) + 2 = 2(x + 3) + 1

0 ≠ 1

b.) 2x + 3(x + 5) = 5(x – 3)

0 ≠ -30

c.) 4(x + 3) = x + 12

x = 3

d.) 4 – (2x + 5) = (–4x – 2)

x = -½

e.) 5(x + 4) – x = 4(x + 5) – 1

0 ≠ -1

I hope this helps

Mila [183]2 years ago

4 0

Answer:

A, B, and C

Step-by-step explanation:

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Number of

jekas [21]

Answer:

The constant rate of change is 3

Step-by-step explanation:

Given

x y

2 6

4 12

6 18

8 24

Required

Determine the constant rate of change

Represent the constant rate of change with k.

k is calculated using:

$k = \frac{y}{x}$

When y = 24; x = 8

So, we have:

$k = \frac{24}{8}$

$k = 3$

7 0

3 years ago

En una clase, 1/3 de los estudiantes eligieron estudiar español como segundo lenguaje vivo. 1/9 eligió italiano, el resto eligió

max2010maxim [7]

Answer:

5/9

Step-by-step explanation:

La clase entera es 1.

1/3 estudian español.

1/9 estudian italiano.

1 - 1/3 - 1/9 estudian alemán.

1 - 1/3 - 1/9 = 9/9 - 3/9 - 1/9 = 5/9

5/9 de los estudiantes estudian alemán.

n = numero total de estudiantes en la clase.

5/9 n = 15

9/5 * 5/9 * n = 15 * 9/5

n = 27

Hay 27 estudiantes en la clase.

27 - 15 = 12

12 estudiantes no estudian alemán.

4 0

3 years ago

an amusement park has 18 rides, 30 games, and 8 water slides. write each ratio in simplest form in two different ways

QveST [7]

Answer:

Step-by-step explanation:

A three tern ratio

What is a three term ratio?

A three-term ratio compares three quantities measured in the

same units.

The ratio of 18 rides, 30 games, and 8 water slides. can be written as

18:30:8

in the simplest form it is expressed as

9:15:4

in other way it is expressed as

9 to 15 to 4

another type of ratio is the two term ratio

e,g 1:2

3 0

3 years ago

A random sample of 10 parking meters in a resort community showed the following incomes for a day. Assume the incomes are normal

GenaCL600 [577]

Answer:

A 95% confidence interval for the true mean is [$3.39, $6.01].

Step-by-step explanation:

We are given that a random sample of 10 parking meters in a resort community showed the following incomes for a day;

Incomes (X): $3.60, $4.50, $2.80, $6.30, $2.60, $5.20, $6.75, $4.25, $8.00, $3.00.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean income = $\frac{\sum X}{n}$ = $4.70

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = $1.83

n = sample of parking meters = 10

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.262 < $t_9$ < 2.262) = 0.95 {As the critical value of t at 9 degrees of

freedom are -2.262 & 2.262 with P = 2.5%}

P(-2.262 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.262) = 0.95

P( $-2.262 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu$ < $2.262 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.262 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.262 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.262 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.262 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $4.70-2.262 \times {\frac{1.83}{\sqrt{10} } }$ , $4.70+ 2.262 \times {\frac{1.83}{\sqrt{10} } }$ ]

= [$3.39, $6.01]

Therefore, a 95% confidence interval for the true mean is [$3.39, $6.01].

The interpretation of the above result is that we are 95% confident that the true mean will lie between incomes of $3.39 and $6.01.

Also, the margin of error = $2.262 \times {\frac{s}{\sqrt{n} } }$

= $2.262 \times {\frac{1.83}{\sqrt{10} } }$ = 1.31

4 0

3 years ago

Find the slope of the line below.

creativ13 [48]

A.
$- \frac{4}{5}$

6 0

4 years ago