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navik [9.2K]
2 years ago
11

2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2=

Mathematics
2 answers:
Sveta_85 [38]2 years ago
7 0

Answer:

48

Step-by-step explanation:

Tomtit [17]2 years ago
3 0

Answer:

48

Step-by-step explanation:

i counted 24 2's and 24 x 2 is 48 also i did the math

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yes because when you multiply 3000 by 10 that gives you a total of 30000 that you paid off

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3 years ago
Please help me with this
kompoz [17]

Answer:

The answer would be X=24

Step-by-step explanation:

Y is multiplied by 3 to get the answer 30. Because they are varied directly you have to multiply the 8 by 3 to get your answer!

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4 0
3 years ago
Read 2 more answers
What equation does the model represent?
Vesnalui [34]

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7 0
3 years ago
A(n)=-6-4(n-1) find the 4th term
egoroff_w [7]

Answer:67738373783

Step-by-step explanation:

3 0
3 years ago
A recent study found that the average length of caterpillars was 2.8 centimeters with a
pogonyaev

Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

\mu = 2.8, \sigma = 0.7.

The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{4 - 2.8}{0.7}

Z = 1.71

Z = 1.71 has a p-value of 0.9564.

1 - 0.9564 = 0.0436.

0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

4 0
2 years ago
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