What’s the original question and I can help!
Area of the parabolic region = Integral of [a^2 - x^2 ]dx | from - a to a =
(a^2)x - (x^3)/3 | from - a to a = (a^2)(a) - (a^3)/3 - (a^2)(-a) + (-a^3)/3 =
= 2a^3 - 2(a^3)/3 = [4/3](a^3)
Area of the triangle = [1/2]base*height = [1/2](2a)(a)^2 = <span>a^3
ratio area of the triangle / area of the parabolic region = a^3 / {[4/3](a^3)} =
Limit of </span><span><span>a^3 / {[4/3](a^3)} </span>as a -> 0 = 1 /(4/3) = 4/3
</span>
Answer:
222.7 cm³ of paper to wrap this.
Step-by-step explanation:
The rectangular prism is SA=2(wl+hl+hw)
Where:
w=5 l=5 h=4
SA= 2((5*5)+(4*5)+(4*5))
SA=2(25+20+20)
SA=2(65)=130cm³
The square base pyramid is 
≈92.69578 cm³
Add the two together 130+92.70 =222.7 cm³
Answer: 12 x 15= 180 cuadrados
juas juas juas 180 + 180 = 360
15 x 15 cm = 360
Step-by-step explanation:
