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mixer [17]
3 years ago
10

Solve the formula for the variable y: 5x+2y=10

Mathematics
1 answer:
belka [17]3 years ago
8 0

Answer:

y=  −5 /2 x+5

Step-by-step explanation:

Let's solve for y.

5x+2y=10

Step 1: Add -5x to both sides.

5x+2y+−5x=10+−5x

2y=−5x+10

Step 2: Divide both sides by 2.

2y /2 = −5x+10 /2

y= −5 /2 x+5

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Simplify (x + 2/ x^2 + 2x -3) / (x + 2/x^2 - x)
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Answer:

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Step-by-step explanation:

* To simplify the rational Expression lets revise the factorization

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* Now lets solve the problem

- We have two fractions over each other

- Lets simplify the numerator

∵ The numerator is \frac{x+2}{x^{2}+2x-3}

- Factorize its denominator

∵  The denominator = x² + 2x - 3

- The last term is negative then the two brackets have different signs

∵ 3 = 3 × 1

∵ 3 - 1 = 2

∵ The middle term is +ve

∴ -3 = 3 × -1 ⇒ the greatest is +ve

∴ x² + 2x - 3 = (x + 3)(x - 1)

∴ The numerator = \frac{(x+2)}{(x+3)(x-2)}

- Lets simplify the denominator

∵ The denominator is \frac{x+2}{x^{2}-x}

- Factorize its denominator

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- Take x as a common factor and divide each term by x

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∵ -x ÷ x = -1

∴ x² - 2x = x(x - 1)

∴ The denominator = \frac{(x+2)}{x(x-1)}

* Now lets write the fraction as a division

∴ The fraction = \frac{x+2}{(x+3)(x-1)} ÷ \frac{x+2}{x(x-1)}

- Change the sign of division and reverse the fraction after it

∴ The fraction = \frac{(x+2)}{(x+3)(x-1)}*\frac{x(x-1)}{(x+2)}

* Now we can cancel the bracket (x + 2) up with same bracket down

 and cancel bracket (x - 1) up with same bracket down

∴ The simplest form = \frac{x}{x+3}

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4 years ago
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