The number can be used to get rid of all fractions is 12
<h3>What number can be used to get rid of all fractions?</h3>
The equation is given as:
6 - 3/4x + 1/3 = 1/2x + 5
The denominator of the fractions are:
4, 3 and 2
The LCM of 4, 3 and 2 is 12
So, we have:
12 * [6 - 3/4x + 1/3] = 12 * [1/2x + 5]
Evaluate the products
72 - 9x + 12 = 6x + 60
Hence, the number can be used to get rid of all fractions is 12
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Answer:
Let's talk through this a one step at a time.
*Since f(x) is concave-up with its vertex on the x-axis, we know f(x) ≥ 0.
*We also know that when we shift a function's domain by a positive number, we shift the function left and when we shift a function's domain by a negative number, we shift the function right. So f(x-5) is f(x) shifted to the right by 5.
*At this point, f(x-5) has its vertex at (5,0).
*When we negate f(x-5), the parabola becomes concave down yet the vertex remains at (5,0). Now we're at -f(x-5). At this point we have -f(x-5)≤0 with a range (-∞,0]
*If we add 2 to create g(x)=2-f(x-5), then we have a concave down parabola with its vertex shifted up by 2, at (5,2). So, g(x) is concave down with its vertex at (5,2). Hence
Answer:
what graph
Step-by-step explanation:
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