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AnnZ [28]
3 years ago
15

Solve -4h - 3 > 4 for h.will give you brainliest

Mathematics
1 answer:
Ber [7]3 years ago
6 0

Answer:

h<-7/4

Step-by-step explanation:

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What is the answer to 7(2y)? Please show your work!
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Step-by-step explanation: You just multiply 7 by 2y

4 0
3 years ago
A) Addition
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Answer:

3+16 divided by 4 is 4.75

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3 years ago
At best buy they have a 42" TV that sells for $1250 and is on sale for 15% off. What
marysya [2.9K]

Answer:

If the television is on sale for 15%, that means that the selling price before tax will be 100 - 15 = 5% of the original price.

1250 * 0.85 = $1062.5 ... this is your selling price BEFORE tax

Now, calculate your tax.

You would pay (1062.5) + (1062.5 * 0.065)  

= 1062.5 + 69.06 (your tax)

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Step-by-step explanation:

5 0
3 years ago
6. Parker, Inc. used Excel to run a least-squares regression analysis, which resulted in the following output: Regression Statis
aleksley [76]

Answer:

"34,814" is the correct solution.

Step-by-step explanation:

The given values are:

Intercept coefficient,

\beta_0 = 23,859

Production coefficient,

\beta_1 = 3.13

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x = 3,500

Now,

The total cost will be:

⇒  \bar{y}=\beta_0+\beta_1 x

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⇒     =23,859+3.13\times 3,500

⇒     =23,859+10,955

⇒     =34,814

4 0
3 years ago
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natta225 [31]
As the fellow above said, the particle does make a U-turn at the vertex, and we can find that out by getting the derivative of s(t) and zeroing it out to get the point of the horizontal tangent.

Bearing in mind that ds/dt is really v(t) or the velocity equation, so when we zero out the ds/dt, is the same as saying the velocity went to 0, since it got zeroed out, and then the particle goes over the vertex and changes direction.

\bf s(t)=2t^3-21t^2+60t+3\implies \boxed{\cfrac{ds}{dt}=6t^2-42t+60}\leftarrow v(t)&#10;\\\\\\&#10;0=6t^2-42t+60\implies 0=t^2-7t+10\implies 0=(t-5)(t-2)&#10;\\\\\\&#10;t=&#10;\begin{cases}&#10;5\\&#10;2&#10;\end{cases}\impliedby \textit{it makes the first turn at the \underline{2 second}}&#10;\\\\\\&#10;\textit{now let's find the acceleration equation, a(t)}&#10;\\\\\\&#10;\boxed{\cfrac{d^2s}{dt^2}=12t-42}\leftarrow a(t)\\\\&#10;-------------------------------\\\\&#10;s(2)=55\qquad \qquad \qquad \qquad a(2)=-18

the negative acceleration value, simply means a decreasing rate of change, so, it means the particle is slowing down and possibly coming to a stop before changing direction again.
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3 years ago
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