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kap26 [50]
3 years ago
12

The line on the graph passes through points A(0,6) and B(3,0). A) Calculate the gradient of line AB. B) Find the gradient of a l

ine perpendicular to AB. C) Find the equation of passing through point A and perpendicular to AB.
Mathematics
1 answer:
yaroslaw [1]3 years ago
7 0

Answer:

-2

Step-by-step explanation:

The gradient = rise/ run

= (0-6)/(3-0)

= -6/3

= -2.

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If P(x) = 12x3 + 11x2 - 9x + 10 and<br> Q(x) = 4x2 – 3x + 2, find<br> P(x) + Q(x)
aniked [119]

Answer:

12x^3+15x^2-12x+12

Step-by-step explanation:

P(x) = 12x^3 + 11x^2 - 9x + 10

Q(x) = 4x^2 – 3x + 2

P(x) + Q(x) = 12x^3 + 11x^2 - 9x + 10+ 4x^2 – 3x + 2

Combine like terms

                 =12x^3+11x^2+4x^2-9x-3x+10+2

                  =12x^3+15x^2-12x+12

4 0
3 years ago
PLEASE help me with this question!! I really need help!
alexdok [17]

Answer:

324π in²

Step-by-step explanation:

The surface area of a sphere = 4πr² ( r is the radius )

Calculate r using the volume (V) formula

V = \frac{4}{3}πr³

Here V = 972π , thus

\frac{4}{3}πr³ = 972π ( divide both sides by π )

\frac{4}{3}r³ = 972 ( multiply both sides by 3 to clear the fraction )

4r³ = 2916 ( divide both sides by 4 )

r³ = 729 ( take the cube root of both sides )

r = \sqrt[3]{729} = 9

Thus

surface area = 4π × 9² = 4π × 81 = 324π in²

5 0
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