Question

Find the distance of a line with endpoints (1, 2) and (7, 4). Round to the nearest tenth.

Answer 1

The distance of the line with endpoints (1, 2) and (7, 4) is 6.32

Step-by-step explanation:

We need to find the distance of the line with endpoints (1, 2) and (7, 4). the distance formula used is:

$d = \sqrt {\left( {x_1 - x_2 } \right)^2 + \left( {y_1 - y_2 } \right)^2 }$

where x₁=1, y₁=2, x₂=7, y₂=4

Putting values in the formula:

$d = \sqrt {\left( {1-7} \right)^2 + \left( {2-4 } \right)^2 }\\d = \sqrt {\left( {-6} \right)^2 + \left( {-2 } \right)^2 }\\d = \sqrt {36+4}\\d = \sqrt {40}\\d=6.32$

So, the distance of the line with endpoints (1, 2) and (7, 4) is 6.32

Keywords: Distance between points

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