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Dovator [93]
2 years ago
7

The population of a certain species of fish in a lake has a relative growth rate of 1-2%. It is estimated the population in the

year 2000 was
1200. What would be the population in 2019?
Mathematics
1 answer:
hichkok12 [17]2 years ago
5 0

Answer:

Fish Population The population of a certain species of fish has a relative growth rate of 1.2 %per year. It is estimated that the population in 2000 was 12 million. (a) Find an exponential model  for the population tyears after 2000 . (b) Estimate the fish population in the year 2005  (c) Sketch a graph of the fish population.

Step-by-step explanation:

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good questing it is something

Step-by-step explanation:

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6 0
1 year ago
Q6. (15 points) IQ examination scores of 500 members of a club are normally distributed with mean of 165 and SD of 15.
melamori03 [73]

Answer:

a) 0.8413

b) 421

c) P_{95} = 189.675

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 165

Standard Deviation, σ = 15

We are given that the distribution of  IQ examination scores is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(IQ scores at most 180)

P(x < 180)

P( x < 180) = P( z < \displaystyle\frac{180 - 165}{15}) = P(z < 1)

Calculation the value from standard normal z table, we have,  

P(x < 180) = 0.8413 = 84.13\%

b) Number of the members of the club have IQ scores at most 180

n = 500

\text{Members} = n\times \text{P(IQ scores at most 180)}\\= 500\times 0.8413\\=420.65 \approc 421

c) P(X< x) = 0.95

We have to find the value of x such that the probability is 0.95

P( X < x) = P( z < \displaystyle\frac{x - 165}{15})=0.95  

Calculation the value from standard normal z table, we have,  

P(z < 1.645) = 0.95

\displaystyle\frac{x - 165}{15} = 1.645\\\\x = 189.675  

P_{95} = 189.675

8 0
3 years ago
The proportion of the total area under a normal curve between two z-scores corresponds to the ______ of that range of scores.
omeli [17]

Answer:

For any normal distribution, the mean and the median will have the same value. For any normal distribution, the proportion corresponding to scores greater than z = +1.00 is exactly equal to the proportion corresponding to scores less than z = -1.00.

Step-by-step explanation:

5 0
2 years ago
Solve by factorizing x² + 8x + 15 + 0
shusha [124]

Download

GET

Algebra

Factor

Factor the polynomial.

(

x

+

3

)

(

x

+

5

)

Tap to view FREE steps...

()|[]√≥

789≤

456/^×>∩∪

123-+÷<π∞

,0.%=

Factor

x

2

+

8

x

+

15

+

0

Regroup terms.

x

2

+

0

+

8

x

+

15

Add

x

2

and

0

.

x

2

+

8

x

+

15

Factor

x

2

+

8

x

+

15

using the AC method.

Tap for fewer steps...

Consider the form

x

2

+

b

x

+

c

. Find a pair of integers whose product is

c

and whose sum is

b

. In this case, whose product is

15

and whose sum is

8

.

3

,

5

Write the factored form using these integers.

(

x

+

3

)

(

x

+

5

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4 0
2 years ago
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