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Dovator [93]
2 years ago
7

The population of a certain species of fish in a lake has a relative growth rate of 1-2%. It is estimated the population in the

year 2000 was
1200. What would be the population in 2019?
Mathematics
1 answer:
hichkok12 [17]2 years ago
5 0

Answer:

Fish Population The population of a certain species of fish has a relative growth rate of 1.2 %per year. It is estimated that the population in 2000 was 12 million. (a) Find an exponential model  for the population tyears after 2000 . (b) Estimate the fish population in the year 2005  (c) Sketch a graph of the fish population.

Step-by-step explanation:

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Alecsey [184]
<span>Dawn was at 6 am. Variables a = distance from a to passing point b = distance from b to passing point c = speed of hiker 1 d = speed of hiker 2 x = number of hours prior to noon when dawn is The first hiker travels for x hours to cover distance a, and the 2nd hiker then takes 9 hours to cover that same distance. This can be expressed as a = cx = 9d cx = 9d x = 9d/c The second hiker travels for x hours to cover distance b, and the 1st hiker then takes 4 hours to cover than same distance. Expressed as b = dx = 4c dx = 4c x = 4c/d We now have two expressions for x, set them equal to each other. 9d/c = 4c/d Multiply both sides by d 9d^2/c = 4c Divide both sides by c 9d^2/c^2 = 4 Interesting... Both sides are exact squares. Take the square root of both sides 3d/c = 2 d/c = 2/3 We now know the ratio of the speeds of the two hikers. Let's see what X is now. x = 9d/c = 9*2/3 = 18/3 = 6 x = 4c/d = 4*3/2 = 12/2 = 6 Both expressions for x, claim x to be 6 hours. And 6 hours prior to noon is 6am. We don't know the actual speeds of the two hikers, nor how far they actually walked. But we do know their relative speeds. And that's enough to figure out when dawn was.</span>
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Irina-Kira [14]
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Given a circle with radius of 2, which is the degree measure of an arc whose length is 1/2 ?
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Convert 13 to fifths.<br> Write your answer as a fraction.
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Step-by-step explanation:

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F(x) = 3x + 6. Find the inverse of f(x).
Levart [38]

Answer:

\tt C) \:\tt f^{-1}(x)=\cfrac{x-6}{3}

Step-by-step explanation:

We're given,

\tt f(x) = 3x + 6

~

\tt y=3x+6

\tt x=3y+6

\tt x-6=3y

\tt y=\cfrac{x-6}{3}

\tt f^{-1}(x)=\cfrac{x-6}{3}

~

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2 years ago
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