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dimaraw [331]
2 years ago
10

I need the lateral area, total area, and the volume. Would greatly appreciate your help!​

Mathematics
1 answer:
iVinArrow [24]2 years ago
4 0

la 4gStep-by-step  im so weird

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Rewrite without paraentheses and simply <br> (Y-2)^2
german

show how to simply that

(y-2)^2

(y-2)(y-2)

Y^2-2y-2y+4

y^2-4y+4

the answer was y^2-4y+4

hope that helps you!!!!

6 0
3 years ago
What is the value of the expression (-8)(6) - (-4)(-5) + (-3)(-6)?
Vlad1618 [11]

-77 is the correct answer. Hope this helped. Comment if you would like a more detailed answer.

5 0
3 years ago
A The length of a rectangle is 4 m more
Lady bird [3.3K]

Given :

  • The length of a rectangle is 4m more than the width.
  • The area of the rectangle is 45m²

⠀

To Find :

  • The length and width of the rectangle.

⠀

Solution :

We know that,

\qquad { \pmb{ \bf{Length \times Width = Area_{(rectangle)}}}}\:

So,

Let's assume the length of the rectangle as x and the width will be (x – 4).

⠀

Now, Substituting the given values in the formula :

\qquad \sf \: { \dashrightarrow x  \times  (x - 4) = 45 }

\qquad \sf \: { \dashrightarrow {x}^{2}  - 4x = 45 }

\qquad \sf \: { \dashrightarrow {x}^{2}  - 4x - 45 = 0 }

\qquad \sf \: { \dashrightarrow {x}^{2}    - 9x+ 5 x - 45 = 0 }

\qquad \sf \: { \dashrightarrow x(x - 9) + 5(x - 9) = 0 }

\qquad \sf \: { \dashrightarrow (x  - 9) (x  + 5) = 0 }

\qquad \sf \: { \dashrightarrow x = 9, \: \: x =  - 5}

⠀

Since, The length can't be negative, so the length will be 9 which is positive.

⠀

\qquad { \pmb{ \bf{ Length _{(rectangle)} = 9\:m}}}\:

\qquad { \pmb{ \bf{ Width _{(rectangle)} = 9 - 4=5\: m}}}\:

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8 0
2 years ago
Help!!!!! Please!!!
miss Akunina [59]
The equation for line E is x = 8.
This is because the line intersects the x-axis at the point (8,0)
5 0
3 years ago
Please please help!! I don't know how to do this!!
nexus9112 [7]
Using cosine law and considering the angle ABC is 89 you can deduce that AC is 6.3
6<6.3
So the largest possible integer is 6
7 0
3 years ago
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