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exis [7]
3 years ago
13

t{12" alt="2\sqrt{3 (\sqrt{27-2\sqrt{12" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Strike441 [17]3 years ago
8 0

Answer: =2\sqrt{3}\sqrt[4]{27-4\sqrt{3}}\quad \left(\mathrm{Decimal:\quad }\:7.33224\dots \right)

Step-by-step explanation:

2\sqrt{3\left(\sqrt{27-2\sqrt{12}}\right)}

=2\sqrt{3\sqrt{27-2\sqrt{12}}}

=2\sqrt{3}\sqrt[4]{27-4\sqrt{3}}

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A water tower is formed by joining two hemispheres to a cylinder and removing the flat surfaces at the ends. The volume needs to
Mrac [35]
Wait what?
removing the flat surfaces...
... oh!
I get it

okey dokey
basicaly find the shape that gives you a volume of 200 cubic meters and and minimizes the amount of materials needed to make the conainer


find the volume
we can take the 2 hemispheres and combine them to get 1 sphere
we can take the cylinder as well
vsphere=(4/3)pir^3
vcylinder=hpir^2
so total volume would be (4/3)pir^3+hpir^2


now find surface area which is the amount of sheet metal we will need to construct it
surface area=lateral area of cylinder+surface area of sphere
lateral area of cylinder=2pirh
surface aea of sphere=4pir^2 
total surface area=2pirh+4pir^2
but, the hemishpere part costs 3 times more
so just say the cylinder part costs 1 dollar per square meter and hemisphere part costs 3 dollars so we mutiply hemishpere part by 3 to get
SAcost=2pirh+12pir^2



so we got
v=200=hpir^2+4/3pir^3
solve for h since the r exponents are tricky
h=\frac{200-\frac{4}{3} \pi r^3}{\pi r^2}
subsitute that for h in the other equation
SAcost=2pirh+12pir^2
SAcost=2 \pi r (\frac{200-\frac{4}{3}\pi r^3}{\pi r^2})+12 \pi r^2
now we simpilify and take the derivitive to find the value of r where SAcost is a minimum
we get at that the derivitive of SAcost is 0 at r=\sqrt[3]{\frac{150}{7 \pi}}
by subsituteion we find that the value of h will be then h=\frac{4(7 \pi -1)\sqrt[3]{7350}}{21\sqrt[3]{\pi}}

aproximately
the radius should be about 1.8964m and the height should be about 53.0789m
5 0
3 years ago
Which of the following is an example of a quadratic equation?
REY [17]

Answer:

B. x^2 - 64 = 0

Step-by-step explanation:

A. x+10 = 33  

B. x^2 - 64 = 0

C. Y-776

D. y = 4x + 6

A quadratic has an term with a power of two

3 0
3 years ago
Read 2 more answers
The table below shows the fifth powers of different numbers:
Lera25 [3.4K]
Part A. Yes, because y=f(x)=x⁵.
Part B. f(4)=2(4)+12=8+12=20.
5 0
3 years ago
What is 11+23/60 as a mixed number
hodyreva [135]

Answer:

the answer is 683/60

Step-by-step explanation:

just multiply 60 by 11 then add 23, or multiply the bottom number by the whole number then add the top number

3 0
3 years ago
if 1 000 bottles of an award-winning wine are to be packed in special gift boxes which can hold six bottles each, calculate how
Anuta_ua [19.1K]

Step-by-step explanation:

Introduction:

This section basically dedicated to the classification of the antennas which are used in different wavelength.

Wire Antennas:

Wire antennas are familiar to the layman because they are seen virtually everywhere on automobiles, buildings, ships, aircraft, spacecraft, and so on.

There are various shapes of wire antennas such as a straight wire (dipole), loop, and helix which are shown in Figure 1.3.

Loop antennas need not only be circular.

They may take the form of a rectangle, square, ellipse, or any other configuration.

The circular loop is the most common because of its simplicity in construction

Aperture Antennas

Aperture antennas may be more familiar to the layman today than in the past because of the increasing demand for more sophisticated forms of antennas and the utilization of higher frequencies.

Some forms of aperture antennas are shown in Figure 1.4.

Antennas of this type are very useful for aircraft and spacecraft applications, because they can be very conveniently flush-mounted on the skin of the aircraft or spacecraft. In addition, they can be covered with a dielectric material to protect them from hazardous conditions of the environment.

Microstrip Antennas

Microstrip antennas became very popular in the 1970s primarily for spaceborne applications.

Today they are used for government and commercial applications. These antennas consist of a metallic patch on a grounded substrate.

The microstrip antennas are low profile, comformable to planar and nonplanar surfaces, simple and inexpensive to fabricate using modern printed-circuit technology, mechanically robust when mounted on rigid surfaces, compatible with MMIC designs, and very versatile in terms of resonant frequency, polarization, pattern, and impedance.

These antennas can be mounted on the surface of high-performance aircraft, spacecraft, satellites, missiles, cars, and even handheld mobile telephones

Array Antennas

Many applications require radiation characteristics that may not be achievable by a single element. It may, however, be possible that an aggregate of radiating elements

in an electrical and geometrical arrangement (an array) will result inthe desiredradiation characteristics.

The arrangement of the array may be such that the radiation from the elements adds up to give a radiationmaximum ina particular directionor directions, minimum in others, or otherwise as desired.

Typical examples of arrays are shownin Figure 1.6.

Usually the term array is reserved for an arrangement in which the individual radiators are separate as shown in Figures 1.6(a/c).

However the same term is also used to describe an assembly of radiators mounted on a continuous structure, showninFigure 1.6(d).

6 0
2 years ago
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