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2 years ago

6

Which of the following expressions is equivalent to 4^-3?

1 answer:

-BARSIC- [3]2 years ago

6 0

Answer:

x(12y+4)

Step-by-step explanation:

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5x=2 written as a fraction

STatiana [176]

Answer:

5x/2

Step-by-step explanation:

4 0

2 years ago

write the x and y coordinate (in the second and third column, respectively) of dilation of quadrilateral ABCD with vertices A(1,

gayaneshka [121]

Answer:

The coordinates of the dillated vertices are $A'(x,y) = (2,2)$ , $B'(x,y) = (4,4)$ , $C'(x,y) = (8,2)$ and $D'(x,y) = (4,-2)$ .

Step-by-step explanation:

From Linear Algebra, we define dilation by the following equation:

$P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)]$ (1)

Where:

$O(x,y)$ - Center of dilation, dimensionless.

$P(x,y)$ - Original point, dimensionless.

$k$ - Scale factor, dimensionless.

$P'(x,y)$ - Dilated point, dimensionless.

If we know that $O(x,y) = (0, 0)$ , $k = 2$ , $A(x,y) = (1,1)$ , $B(x,y) = (2,2)$ , $C(x,y) = (4,1)$ and $D(x,y) = (2,-1)$ , then the dilated points are, respectively:

Point A

$A'(x,y) = O(x,y) + k\cdot [A(x,y)-O(x,y)]$ (2)

$A'(x,y) = (0,0) + 2\cdot [(1,1)-(0,0)]$

$A'(x,y) = (2,2)$

Point B

$B'(x,y) = O(x,y) + k\cdot [B(x,y)-O(x,y)]$ (3)

$B'(x,y) = (0,0) + 2\cdot [(2,2)-(0,0)]$

$B'(x,y) = (4,4)$

Point C

$C'(x,y) = O(x,y) + k\cdot [C(x,y)-O(x,y)]$

$C'(x,y) = (0,0) + 2\cdot [(4,1)-(0,0)]$

$C'(x,y) = (8,2)$

Point D

$D'(x,y) = O(x,y) + k\cdot [D(x,y)-O(x,y)]$

$D'(x,y) = (0,0) + 2\cdot [(2,-1)-(0,0)]$

$D'(x,y) = (4,-2)$

The coordinates of the dillated vertices are $A'(x,y) = (2,2)$ , $B'(x,y) = (4,4)$ , $C'(x,y) = (8,2)$ and $D'(x,y) = (4,-2)$ .

4 0

3 years ago

2x < 2<br> What is the value of x?

TEA [102]

X can be a value of any number less than 0.9.
Solved, this is x<1 as an inequality.

6 0

3 years ago

What function type can have vertical asymptotes?

Sonja [21]

Rational functions of the form
f(x)= polynomial in x / another polynomial in x

See example plot attached.

8 0

3 years ago

The length of a rectangle is 5 meters greater than the width. The perimeter is 150 meters. Find the width AND the length.

oee [108]

Answer:

L=62.5 W=12.5

Step-by-step explanation:

L=5W

150=2W+2(5W)

75=W+5W

75=6W

W=12.5

12.5×5=62.5

62.5+62.5+12.5+12.5=150

7 0

3 years ago