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Cloud [144]
3 years ago
7

In pigeons, the allele for normal feathers (F) is dominant to the allele for frizzy feathers (f). If a purebred, normal-feathere

d bird is crossed with a frizzy feathered bird, what percentage of the offspring will possess normal feathers?
Mathematics
1 answer:
Irina-Kira [14]3 years ago
4 0

Answer:

Step-by-step explanation:

100% because if you do a punnett square there is always a dominant alle so they are all Ff, when there is a dominant alle present the offspring gets the dominant trait.

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Elena surveyed her classmates to see how many like to make jewelry. When she asked 20 of her classmates, 50 percent said they li
nordsb [41]

10 students of Elena's classmates like to make jewellery.

<u>Step-by-step explanation:</u>

Let total no.of classmates who liked the jewellery = x

Here, in the given problem, given she asked her classmates '20'. So, it clearly shows that total number of students/classmates = 20. Also, in that, 50% said like to make jewellery. Now find 'x' as below,

                    x = 50 \% \text { of } 20

                    x = \frac{50}{100} \times 20

                    x = 10

Hence, the total number of classmates who liked to make Jewellery = 10

5 0
3 years ago
Which ordered pair does not represent a point on the square?
Vikentia [17]

Answer:

D

Step-by-step explanation:

-2, 1 is not a point in the square but - 2, 2 is so the answer should be D -2,1

If my answer helped, kindly mark me as the brainliest!!

7 0
3 years ago
Read 2 more answers
the number is less than 20. it is an odd one-digit number. it is not the number of sides of a triangle. It can be divided by thr
Elden [556K]
The answer is 9 because its an odd number, not the sides of a triangle, can be divided be 3, and is a single digit number.
3 0
3 years ago
Read 2 more answers
In a zoo there are 17 more monkeys than lions and 30 more lizards than lions. If there were 151 monkeys, lions and lizards in to
kvv77 [185]
If the amount of monkeys is m, lions is a, and lizards is b, then a+b+m=151, 17+a=m (since there are 17 more monkeys than lions), and 30+a=b. Substituting those values in (17+a=m and 30+a=b), we have 30+17+a+a+a=151=47+3a. Subtracting 47 from both sides, we get 104=3a. Next, we can divide both sides by 3 to get 104/3=a (the number of lions), 104/3+17=the number of monkeys, and 104/3+30=the number of lizards. Somehow we end up with a fraction (not a whole number), so there are 2/3rds of monkeys floating around using this logic.


8 0
3 years ago
Andy wrote the following statement:
olasank [31]
I believe it would be B. Because, an isoceles triangle is a triangle with 2 equal sides and 1 is not equal ... SO, more than one triangle could be drawn from this information. Because, 55 could be the uneven side for many triangles. So, B.  Andy is incorrect, because more than one triangle can be drawn from the given info. :)

<u><em>B.</em></u><em /> Hope it helps!!! :)<em /><em />
3 0
3 years ago
Read 2 more answers
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