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ololo11 [35]
3 years ago
10

At the movie theatre, child admission is $5.20 and adult admission is $9.00 . On Saturday, 156 tickets were sold for a total sal

es of $1027.80 . How many adult tickets were sold that day?
Mathematics
1 answer:
stiks02 [169]3 years ago
3 0

We can solve this by using systems of equations.

Let's find our first formula, how much money was made using the tickets.

5.20x + 9y = 1027.80

Here x is how many child tickets we sold and y is how many adult tickets we sold. Now that we have defined that, we can make another formula for the total tickets sold!

x + y = 156 since we sold 156 tickets that could be any combination of child and adult tickets.

Let's solve this system. I'm going to use <em>substitution</em> so I'm going to take our second formula and subtract both sides by x to get y = 156 - x.

Now I will plug this in the first equation for y to get You plug it in for y to get 5.20x + 9 (156-x) = 1027.8.

From this you can solve for x to get x = 99.

Since x + y = 156

99 + y = 156

y = 57

There were 99 child tickets and 57 adult tickets.

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Answer: x = 9/4

Step-by-step explanation:

4x+12+2=23

4x+14 = 23

4x = 9

x = 9/4

7 0
3 years ago
Read 2 more answers
A certain bookstore chain has two stores, one in San Francisco and one in Los Angeles. It stocks three kinds of books: hardcover
victus00 [196]

Answer:

Answer:

a. Sales from January to June: Matrix B6

                             Hard    Soft       Plastic

San Francisco     4,200   7,200     12,000

Los Angeles       2,400    1,200      3,000

b) Ending Inventory: Matrix D:

                           Hard      Soft      Plastic

San Francisco      400     4,800     3,000

Los Angeles      1,600     7,800     3,000

Step-by-step explanation:

a) Data and Calculations:

Stock on January 1: Matrix A

                              Hard    Soft       Plastic

San Francisco       1,000   3,000    6,000

Los Angeles         1,000   6,000    3,000

Sales in January: Matrix B

                             Hard    Soft       Plastic

San Francisco       700     1,200     2,000

Los Angeles         400       200        500

Restocking: Matrix C

                          Hard    Soft       Plastic

San Francisco    600   1,500      1,500

Los Angeles      500     500        500

Total Sales over the first 6 months =

Matrix B * 6 = Matrix B6

Sales in January: Matrix B

                             Hard    Soft       Plastic

San Francisco       700     1,200     2,000

Los Angeles         400       200        500

* 6

=

Sales from January to June: Matrix B6

                            Hard    Soft       Plastic

San Francisco     4,200   7,200     12,000

Los Angeles       2,400    1,200      3,000

Matrix C6 = Matrix C * 6

=

Restocking: Matrix C6

                          Hard     Soft       Plastic

San Francisco  3,600   9,000      9,000

Los Angeles    3,000   3,000      3,000

Inventory at the end of June =

Matrix A + Matrix C6 - Matrix B6

= Matrix D

Stock on January 1: Matrix A

                             Hard    Soft       Plastic

San Francisco       1,000   3,000    6,000

Los Angeles         1,000   6,000    3,000

+

Restocking: Matrix C6

                           Hard     Soft       Plastic

San Francisco  3,600   9,000      9,000

Los Angeles    3,000   3,000      3,000

-

Sales from January to June: Matrix B6

                             Hard    Soft       Plastic

San Francisco     4,200   7,200     12,000

Los Angeles       2,400    1,200      3,000

Ending Inventory: Matrix D:

                            Hard      Soft       Plastic

San Francisco      400     4,800     3,000

Los Angeles      1,600     7,800     3,000

3 0
3 years ago
A farmer finds there is a linear relationship between the number of bean stalks, n, she plants and the yield, y, each plant prod
-Dominant- [34]

Answer:

Step-by-step explanation:

Given that a farmer finds there is a linear relationship between the number of bean stalks, n, she plants and the yield, y, each plant produces

When we consider this graph as a straight line, the two points lying on the line would be

(30, 30) and (34, 28) taking n as horizontal and y vertical

Using two point equation we find that

the equation of the line is

\frac{y-y_1}{y_2-y_1} =\frac{x-x_1}{x_2-x_1}

Substitute the points as x =n

\frac{y-30}{28-30} =\frac{x-30}{34-30}\\y-30 = -0.5(x-30)\\y = -0.5x+45

is the linear relationship between n and y

7 0
3 years ago
Greg plays baseball at a field where the baseball diamond is a square with each side of the square measuring 90 feet. If the bas
tiny-mole [99]

Answer:

The diagonal of a square with 90 ft. per side is 127.28 which should be rounded down to 127 and the throw from 2nd to 3rd is 90 ft totaling 217 ft

5 0
3 years ago
Which of the following correctly completes the square for the equation
rjkz [21]

Answer:

A. (x + 2)^2 = 31.

Step-by-step explanation:

x^2 + 4x = 27

x^2 + 4x - 27 = 0

A. (x + 2)^2 = 31

x^2 + 4x + 4 - 31 = 0

x^2 + 4x - 27 = 0

This option corresponds to the given equation, so it is correct.

B. (x + 2)^2 = 43

x^2 + 4x + 4 - 43 = 0

x^2 + 4x - 39 = 0

This does not correspond to the equation.

C. (x + 4)^2 = 31

x^2 + 8x + 16 - 31 = 0

x^2 + 8x - 15 = 0

This does not correspond to the equation.

D. (x+4)^2 = 43

x^2 + 8x + 16 - 43 = 0

x^2 + 8x - 27 = 0

This does not correspond to the equation.

So, your answer is A. (x + 2)^2 = 31.

Make sure to SUBMIT and check your PREVIOUS answers to make sure they are right! XD Also, hope this helps!

7 0
3 years ago
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