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3 years ago

14

A bag of fertilizers covers 30 square yard of lawn.find how many bags of fertilizers should be purchased to cover a rectangular

lawn 25 yards by 18 yard

1 answer:

lidiya [134]3 years ago

4 0

Answer:

15 bags

Step-by-step explanation:

25 * 18 yard^2 = area

so, Area/Fertilizercoverrate = what we want.

25*18/30 = <u><em>15 bags</em></u>

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A cookie factory uses 1/6 of a bag of flour in each batch of cookies. The factory uses 5/6 of a bag of flour yesterday. How many

aliina [53]

From the information given, each batch of cookies requires 1/6 of a bag of flour.

So how many batches can be gotten from 5/6 of the bag of flour?

We form an equation

1batch = 1/6

x batches = 5/6

Where x is the number of batches from 5/6 bag of flour.

Cross multiplying this equation we get:

x * 1/6 = 1 * 5/6

simplify it:

x * 0.16 = 1 * 0.83

x = 1 * 0.83 / 0.16

x = 0.83 / 0.16

x = 5.2

Therefore factory made approximately 5 batches of cookies yesterday.

7 0

3 years ago

X 20) Becca has 3 times more games than Susan has. Write an algebraic

vova2212 [387]

Answer:

3*x

Step-by-step explanation:

If Becca has 3 times the amount of games as Susan then you would multiply the number of games Susan has by 3. So we can use X (or another letter) to represent the number of games Susan has. Giving us 3*x

7 0

3 years ago

8. An artist creates 8 identical ceramic bowls. The bowls contains some glass and 59.2 pounds of clay. The artist uses a

Aleksandr [31]

Answer:

021110321....1.12...1.1.631.6301

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

If k=9 and x=5, find the value of the expression: <br> 2k - X<br><br> Please hurry

il63 [147K]

Answer:

$\huge\boxed{13}$

Step-by-step explanation:

= 2k - x

Given that k = 9, x = 5

= 2(9) - 5

= 18 - 5

= 13

$\rule[225]{225}{2}$

Hope his helped!

<h3>~AH1807</h3>

8 0

3 years ago

A random sample of 36 students at a community college showed an average age of 25 years. Assume the ages of all students at the

Pavel [41]

Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average age = 25 years

$\sigma$ = population standard deviation = 1.8 years

n = sample of students = 36

$\mu$ = population average age

So, 98% confidence interval for the average age, $\mu$ is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.3263) = 0.98

P( $-2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < ${\bar X - \mu}$ < $2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

P( $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < $\mu$ < $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ , $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ]

= [ $25 - 2.3263 \times {\frac{1.8}{\sqrt{36} }$ , $25 + 2.3263 \times {\frac{1.8}{\sqrt{36} }$ ]

= [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

8 0

3 years ago