Answer:
4 moles
Explanation:
First, let's find the molar mass of AgCl. The molar mass of Ag is 107.87 and the molar mass of chlorine is 35.45 so the total mass is 107.87 + 35.45 = 143.32 grams per mole. Now all we need to calculate is 573.28 / 143.32 = 4 moles.
Answer:
Percent yield = 92.5%
Explanation:
The question asks for the percent yield which can be defined as:
Where the actual yield is <em>how much product was obtained</em>, in this case 6.11 g of Ca(OH)₂, and the theoretical yield is <em>how much product could be obtained with the given reactants theoretically</em>, that is if the reaction would work perfectly. So we need to calculate first the theoretical yield.
1. First lets write the chemical equation reaction correctly and check that it is balanced:
CaO + H₂O → Ca(OH)₂
2. Calculate the amount of product Ca(OH)₂ that can be obtained with the given reactants (theoretical yield), which are 5.00g of CaO and excess of water. So the amount of CaO will determined how much Ca(OH)₂ we can obtained.
For this we'll use the molar ratio between CaO and Ca(OH)₂ which we see it is 1:1. For every mol of CaO we'll obtain a mol of Ca(OH)₂. So lets convert the 5.00 g of CaO to moles:
Molar Mass of CaO: 40.078 + 15.999 = 56.077 g/mol
moles of CaO = 5.00 g / 56.077 g/mol = 0.08916 moles
As we said before from the molar ratio moles of Ca(OH)₂ = moles of CaO
So the moles of Ca(OH)₂ that can be obtained are 56.077 g/mol
We need to convert this value to grams:
Molar Mass of Ca(OH)₂ = 40.078 + (15.999 + 1.008)*2 = 74.092 g/mol
Theoretical yield of Ca(OH)₂ = 0.08916 moles x 74.092 g/mol = 6.606 g
3. Calculate the percent yield:
Percent yield = (6.11 g / 6.606g) x 100 = 92.5 %
We all struggle in some subjects, you do badly when you don't try, and sometimes we try and can't get the answer, I'll help with that. :)
The first answer is CO2(g), CO2 is a gas, and all gas have... 4) No definite shape, no definite volume.
A piece of ice, a block of wood, and a ceramic cup are solids. They have shapes that do not change and volumes that can be measured. Any matter that is a solid has a definite shape and a definite volume.
A liquid takes the shape of what holds it, besides a flat surface, which will just evidently, take the shape of a flat surface. A liquid has a definite volume, because the volume of a liquid is constant because forces of attraction keep the particles loosely together.
Gases attempt to fill a container of any shape or size. Therefore, it has no definite shape.
There are forces of attraction among the particles in all matter, therefore, it has no definite volume.
The second question might become easier with the explanation above. A liquid has a definite volume because the forces of attraction are loosely together! Therefore, it has a definite volume, but it will take the shape of it's container.
This means... Yes! 2) It retains its original volume but changes shape.
This one is easy. To convert one gram of a solid at its normal heating point to a liquid at the same temperature, is the 1) Heat of Vaporization.
Heat of Vaporization is the amount of heat energy required to convert one gram of a substance from a liquid to a gas.
The third question, the molecules for H20, in a solid phase are always in an geometric and arranged pattern.
Most solids are arranged in geometric and arranged patterns, and since H20 is not in its indefinitely shaped liquid phase, it has a definite shape and thus, retains a repeating (geometric) pattern.
(Note- Some solids like wax or rubber do not have an arranged or geometric pattern.)
The “average of a kinetic energy” is defined as the vitality of movement of particles of a framework.
Or in simpler terms, “energy motion”.
So when temperature increases, the average kinetic energy of a molecule(s) 1) increases.
The mass of the salt converted into moles divided by the liters of water in a solution would give the Molarity (M) or concentration of the solution. The simplest way to change the solution would be to change the amount of solute or solvent in a solution.
The correct answer is B. Adipic Acid.
According to coursehero.com
