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Aliun [14]
2 years ago
9

1.Nuclear charge decreases as the atomic number increases.Immersive Reader

Chemistry
1 answer:
astra-53 [7]2 years ago
6 0

1.Nuclear charge decreases as the atomic number increases.Immersive Reader

Answer - True

2.In alkali metals, the atomic radius of potassium is greater than

Answer - Lithium

3.While moving across the periodic table from left to right there is an increase in atomic radius.

Answer - False

4.When moving from gold to lead, the atomic radius increases.

Answer - True

5.The picometer is the unit used to measure atomic radii.

Answer - True

6.Which of the following is larger in atomic size?

Answer - Boron

7.Chlorine has a larger atomic radius than fluorine.

Answer - True

8.Atomic size increases across a period.

Answer - False

9.The atomic radius of a nitrogen atom is 70 pm. What is the distance between the nuclei of two bonded nitrogen atoms in a N2 molecule

Answer - 140 pm

10.Arrange the following atoms in order of decreasing atomic radius:

Ga, As, Sn, Sb, Te

Answer - a. Sn, Sb, Te, Ga, As

<em><u>Thanks for joining brainly community</u></em><em><u>.</u></em>

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If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant
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<h3>Answer:</h3>

              Excess Reagent =  NBr₃

<h3>Solution:</h3>

The Balance Chemical Equation for the reaction of NBr₃ and NaOH is as follow,

                       2 NBr₃ + 3 NaOH   →   N₂ + 3 NaBr + 3 HBrO

Calculating the Limiting Reagent,

According to Balance equation,

               2 moles NBr₃ reacts with  =  3 moles of NaOH

So,

           40 moles of NBr₃ will react with  =  X moles of NaOH

Solving for X,

                       X  =  (40 mol × 3 mol) ÷ 2 mol

                       X  =  60 mol of NaOH

It means 40 moles of NBr₃ requires 60 moles of NaOH, while we are provided with 48 moles of NaOH which is Limited. Therefore, NaOH is the limiting reagent and will control the yield of products. And NBr₃ is in excess as some of it is left due to complete consumption of NaOH.

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