The correct answer is the third option. I just got it correct.
I am not to sure but I would go for B. identity.
Answer:
50
Step-by-step explanation:
v = the original speed of the cruise
d = 225 km the distance passed
t = d/v = 225/v the total time of the travel
v*1.5 + (v + 10)(d/v - 1.5 - 0.5) = d (using the formula distance = speed*time)
1.5v + (v + 10)(225/v - 2) = 225
Look at the images to see the solved equation
The length of OM is 4/3 the length of OJ, and the length of ON is 4/3 the length of OK. Thus, two pairs of sides from the triangles are proportional to each other.
Also, angle O from one of the triangles is equal to angle O of the other triangle because they are the same angle.
Thus, the two triangles are similar by SAS (side-angle-side) similarity theorem. This theorem is quite similar to the SAS congruence theorem.
To make a similarity statement, we just have to match corresponding parts when naming the triangle.
Similarity statement: ΔOJK~ΔOMN
9514 1404 393
Answer:
9n^4
Step-by-step explanation:
The divisor and quotient can be interchanged to find the divisor:

Such division is carried out by first finding the quotient of the highest-degree terms:

This value is used to multiply the denominator and subtract that product from the numerator to find the new numerator. The new numerator is zero, so the value that goes in Blank 1 is ...
9n^4
_____
The attachment shows the long division.