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g100num [7]
3 years ago
5

How do you do this geometry question?

Mathematics
2 answers:
hram777 [196]3 years ago
7 0

Answer: B: 150°

Step-by-step explanation:

|EF|=\sqrt{1^2-(\dfrac{1}{2})^2}}=\sqrt{\dfrac{3}{4} } =\dfrac{\sqrt{3} }{2} \\\\tan(\alpha)=\dfrac{1-\dfrac{\sqrt{3} }{2} }{\dfrac{1}{2} } =2-\sqrt{3} \Longrightarrow\ \alpha=15^o \\\\mes\widehat{BEC}=180^o-2*15^o=150^o\\\\Answer\ B

KATRIN_1 [288]3 years ago
6 0

Answer:

Ans: A 160

Step-by-step explanation:

(Hope this helps have a great day :)

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