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goblinko [34]
3 years ago
14

Mr. Chen spends $32 for tickets to a play. If the tickets cost $8 each how many tickets does Mr. Chen buy?

Mathematics
2 answers:
Olegator [25]3 years ago
8 0
Hey!

You must divide the amount of money he spent by the amount of money each ticket costs:

32 ÷ 8 = 4

So, Mr. Chen bought 4 tickets.
leva [86]3 years ago
5 0
The answer is 4 because take 32 divided by 8 and it will give u 5
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4096 ways : 8 candy toppings plus 4 fruit toppings is 12. Then 2^12 (2 different types of toppings and the 12 of total toppings) = 4096
4 0
3 years ago
PLEASE HELP! 40 POINTS
Anuta_ua [19.1K]

Answer:

-1 -1

Step-by-step explanation:

because thats were they touch

8 0
2 years ago
Two similiar rectangles have corresponding sides in the ratio 10:3. What is the ratio of their areas
lianna [129]

Answer:

Step-by-step explanation:

The ratio of its areas is equal to

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

In this problem the scale factor is equal to the ratio 10:3

Let

z-------> the scale factor

so

z2=(10/3)2=100/9

7 0
3 years ago
Pleasantburg has a population growth model of P(t)=at2+bt+P0 where P0 is the initial population. Suppose that the future populat
yulyashka [42]

Answer:

The population will reach 34,200 in February of 2146.

Step-by-step explanation:

Population in t years after 2012 is given by:

P(t) = 0.8t^{2} + 6t + 19000

In what month and year will the population reach 34,200?

We have to find t for which P(t) = 34200. So

P(t) = 0.8t^{2} + 6t + 19000

0.8t^{2} + 6t + 19000 = 34200

0.8t^{2} + 6t - 15200 = 0

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

0.8t^{2} + 6t - 15200 = 0

So a = 0.8, b = 6, c = -15200

Then

\bigtriangleup = 6^{2} - 4*0.8*(-15100) = 48356

t_{1} = \frac{-6 + \sqrt{48356}}{2*0.8} = 134.14

t_{2} = \frac{-6 - \sqrt{48356}}{2*0.8} = -141.64

We only take the positive value.

134 years after 2012.

.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.

So the population will reach 34,200 in February of 2146.

6 0
3 years ago
Is it true that any set of data can be displayed using a line graph
fenix001 [56]
No, line graphs are used only to show change over time
6 0
3 years ago
Read 2 more answers
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