Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900
There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20
The price of an advance ticket was 20.
The price of a same-day ticket was 15.
Answer:
The formula for area is length times width.
it's 8m long, and 6m wide. When we multiply it, we get 48m that is for one side of the cube, so we count how many sides there is. There's 6, so we multiply 6 times 48 and the complete surface area for the whole cube is 288m
Answer:
276000
Step-by-step explanation:
keep the 2 and 7, but since 964 rounds up to 1000, add 1000 to the 5000. That makes 276000
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