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schepotkina [342]
2 years ago
7

Need help finding the answers

Mathematics
1 answer:
Alex777 [14]2 years ago
7 0
8=384        9=248   hope this helped 
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The area of a rhombus whose diagonals are of lengths 10 cm and 8.2 cm is ____
ololo11 [35]

Answer:

area= 41 cm^2

Step-by-step explanation:

area=5 x 8.2 = 41 cm^2

divide the rhombus in half either way and you have two identical triangles.

area of triangle =0.5 x base x height

double that for the two triangles and you have the area of the rhombus.

8 0
2 years ago
Please help with geometry homework!!!!
EleoNora [17]

Area of Parallelogram ABCD is equivalent to the area of rectangle AXBY.

Area of rectangle AXBY= Length AX * Length AB= 3 ft * 4√2 ft = 12√2 sq.ft.

Thus Area of Parallelogram is 12√2 sq.ft.

4 0
3 years ago
Find the area of the circle. Leave your answer in terms of Pi. Diameter is 14 ft.
QveST [7]

Answer:

The area of the circle is 49\pi\ ft^{2}

Step-by-step explanation:

we know that

The area of a circle is equal to

A=\pi r^{2}

we have

r=14/2=7\ ft -----> the radius is half the diameter

substitute the value

A=\pi (7)^{2}

A=49\pi\ ft^{2}

7 0
3 years ago
Read 2 more answers
If the function f(x) = 4x^2 - x + 3, evaluate f(-2)
ira [324]

Answer: 21

Step-by-step explanation: f(-2) = 4· (-2)²-(-2) + 3 = 4·4 +2 +3

5 0
2 years ago
Find the sum of the infinite series 1/3+4/9+16/27+64/81+.... if it exists.
pshichka [43]
9/27, 12/27, 16/27

So this is a geometric sequence as each term is 4/3 the previous term.

Since the common ration is greater than one the sum of the series diverges, it does not exist.  (The sum just keeps getting larger and larger)

For a geometric series to have a sum r^2<1

So that the normal sum....

s(n)=a(1-r^n)/(1-r)   becomes if r^2<1

s=a/(1-r)
6 0
3 years ago
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