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3 years ago

8

A local theater charges $3 for student tickets and $5 for adult tickets. If they sold 85 tickets for a total of 301.00, how many

adult tickets did they sell

2 answers:

andreyandreev [35.5K]3 years ago

6 0

Answer:

20

Step-by-step explanation:

harkovskaia [24]3 years ago

5 0

Answer:

20

Step-by-step explanation:

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Need help in this question

Anarel [89]

Answer:

B) 9

Step-by-step explanation:

110 + 75 + 11x - 9 + 8x + 13 = 360

19x + 189 = 360

19x (+ 189 - 189) = 360 - 189

19x = 171

19x/19 = 171/19

x = 9

3 0

3 years ago

Help me will give brain

Marat540 [252]

Answer:

Umm sure what you want..

3 0

3 years ago

The balcony of an apartment is 4 feet by 7 feet. On a scale drawing of the apartment, the balcony is 0.8 inch by 1.4 inches, and

-Dominant- [34]

Answer:

The actual dimensions of the kitchen are $12\ ft$ by $14\ ft$

Step-by-step explanation:

step 1

Find the scale of the drawing

To find the scale , remember that is equal to the ratio of the corresponding dimension in the drawing divided by the corresponding actual dimension

so

$\frac{0.8}{4}\frac{in}{ft}=0.2\frac{in}{ft}$

step 2

To find the actual dimensions of the kitchen, divide the dimension in the drawing by the scale

so

$2.4\ in=2.4/0.2=12\ ft$

$2.8\ in=2.8/0.2=14\ ft$

6 0

3 years ago

A rectangle is such that the length of 2 of each adjacent sides are in the ratio 1:3. A similar rectangle has 1 side of 6cm. Fin

Sliva [168]

Answer:

18 cm ;

2 cm

Step-by-step explanation:

Length of each adjacent side = 1 :3

If 1 side = 6 ; the possible values of the adjacent side ;

That is side 2 ÷

If side 1, which is 6cm is the ratio 1 ; then side 2 = 6cm * 3 = 18 cm

If side 1, which is 6cm is the ratio 3 ; then side 2 = 6cm / 3 = 2 cm

Hence, the two Possible values of the adjacent side = 18 cm or 2 cm

8 0

3 years ago

An arithmetic sequence with a third term of 8 and a constant difference of 5

Vanyuwa [196]

$\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\ \hrulefill\\[0.5em] a_3=8\\ n=3\\ d=5 \end{cases} \\\\\\ a_3=a_1+(3-1)5\implies 8=a_1+(2)5 \\\\\\ 8=a_1+10\implies -2=a_1 \\\\\\ \begin{cases} a_1=-2\\ d=5 \end{cases}\implies a_n=-2+(n-1)d$

5 0

3 years ago