Answer:
A, G2.
Explanation:
G2, the second gap, occurs directly after S phase, the synthesis of new DNA.
Answer:
The correct answers are A, B and D. The Clean Air Act was important because it emphasized cost-effective methods to protect the air; encouraged people to study the effects of dirty air on human health; and created a regulation that makes any activities that pollute the air illegal.
Explanation:
The Clean Air Act is a federal federal law designed to control air pollution nationwide. The Environmental Protection Agency (EPA) is required to develop and enforce the regulations to protect the general public from exposure to air pollutants that are known to be dangerous to human health. The 1963 law established a basic research program, which was expanded in 1967. The main changes to the law, which require regulatory controls of air pollution, were promulgated in 1970, 1977 and 1990.
The 1970 amendments significantly expanded the federal mandate by demanding broad federal and state regulations, both for fixed sources of pollution (industrial) and mobile sources.
In 1990 provisions were added to deal with acid rain, depletion of the ozone layer and toxic air pollution, and a program of national permits of fixed sources was established. Also new requirements were established for the reformulation of gasoline, the adjustment of Reid vapor pressure (RVP), which measures the volatility of gasoline; and the norms to control the evaporation emissions of the gasoline.
The Clean Air Act is important because it was the first important environmental law in the United States to include a disposition regarding citizen demands. Numerous local and state governments have promulgated similar laws, either the execution of federal programs or to fill important loopholes at the local level in federal programs.
A uniform region occupies an area based on a homogeneous characteristic is a true statement. Regions can also be based on ecological features and as well as the location of it region itself.
Smaller cube (1 cm X 1 cm X 1 cm)
<span>The surface area of one side = 1 cm X 1 cm = 1 <span>cm2</span></span>
<span>There are 6 sides, total SA = 6 X 1 <span>cm2</span> = 6 <span>cm2</span></span>
<span>Volume = 1 cm X 1 cm X 1 cm = 1 cubic cm (1 <span>cm3</span>)</span>
<span>Surface to Volume Ratio = 6 <span>cm2</span>/1 <span>cm3</span> = 6 <span>cm2/cm3</span></span>
Larger cube (6 cm X 6 cm X 6 cm)
<span>The surface area of one side = 6 cm X 6 cm = 36 <span>cm2</span></span>
<span>There are 6 sides, the total SA = 6 X 36 <span>cm2</span> = 216 <span>cm2</span></span>
<span>Volume = 6 cm X 6 cm X 6 cm = 216 <span>cm3</span></span>
<span>Surface to Volume Ratio = 216 <span>cm2</span>/216 <span>cm3</span> = 1 <span>cm2/cm3</span></span>
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