1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andrew [12]
3 years ago
13

X + 2 = 5x solve for x.

Mathematics
2 answers:
ivanzaharov [21]3 years ago
8 0

Answer:

x = 1/2 or 0.5

Step-by-step explanation:

Subtract 2 from both sides of the equation

x + 2 - 2 = 5x -2

Simplify

x = 5x -2

Subtract 5x from both sides of the equation

x = 5x -2

x - 5x = 5x - 2 - 5x

Solution

x = 1/2

Hope this helps!! :))

https://brainly.com/

USPshnik [31]3 years ago
7 0
X=3 which means 3+2 simplified
You might be interested in
Please calculate this limit <br>please help me​
Tasya [4]

Answer:

We want to find:

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}

Here we can use Stirling's approximation, which says that for large values of n, we get:

n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

And we can rewrite it as:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}

7 0
3 years ago
The night watchman in a factory cannot guard both the safe in back and the cash register in front. The safe contains $6000, whil
Zolol [24]

Answer:

The guard should be positioned at the safe

Step-by-step explanation:

The night watchmen should be positioned to guard whichever place gives the highest expected value to the thief.

The expected value of robbing the safe is:

EV_{s} = \$ 6000*0.2\\EV_{s} = \$ 1200

The expected value of robbing the cash register is:

EV_{r} = \$ 1000*0.8\\EV_{r} = \$ 800

Therefore, the guard should be positioned at the safe since it yields a higher expected value to the thief in case he tries to rob it.

7 0
3 years ago
Complete the following statement with the number that makes it true.
ANEK [815]

1 kg = 1000 g

so answer is 1000

8 0
4 years ago
Can you please help me​
Slav-nsk [51]

Answer:

C.

Step-by-step explanation:

Hi there!

To answer this, we must set it up as

3x(2x^4-12x^2+7)

Now we just use the distributive property to solve.

this becomes 6x^5-36x^3+21x

I hope this helps!

4 0
3 years ago
What steps would you follow in order to solve the equation?
Monica [59]

Answer:

c. add 4 on each side and multiply by 8

Step-by-step explanation:

4 0
3 years ago
Other questions:
  • A quiz consists of 10 true or false questions. To pass the quiz a student must answer at least eight questions correctly.
    10·1 answer
  • Problem 7-35 A satellite range prediction error has the standard normal distribution with mean 0 NM and standard deviation 1 NM.
    10·1 answer
  • How can 52 over 9 be expressed as a decimal? HEEEEEEEEEEEEELLLLLLLLLLLLLLPPPPP
    12·1 answer
  • A family has four daughters, Molly, Daisy, Rosie and Tilly.
    8·2 answers
  • Which statement is true about a translation?
    12·1 answer
  • Please answer.
    6·1 answer
  • -2(-3n<br><img src="https://tex.z-dn.net/?f=%20-%202%28%20-%203n%20%7B2%29%7D%5E%7B2%7D%20" id="TexFormula1" title=" - 2( - 3n {
    14·1 answer
  • Can anyone help me? Will give Brainly + 15 pts
    7·1 answer
  • Two mechanics worked on a car. The first mechanic charged $105 per hour, and the second mechanic charged $85 per hour. The mecha
    13·1 answer
  • James determined that these two expressions were equivalent expressions using the values of x = 4 and x = 6. Which statements ar
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!