What is 1.7¯ expressed as a fraction in simplest form?
2 answers:
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Answer:
1. (a) 32 (b) 8
2. (a) 48.33 (b) 92.75 (c) 9.63
3. We observe that sample mean of air quality index in Pomona is higher that that of Anaheim which indicates that the level of air pollution is higher in Pomona and there is more health concern here.
On the other hand, the variation in air quality index is higher in Anaheim than in Pomona as Anaheim has higher variance and standard deviation for air quality index which means that there are not much fluctuations in air quality index in Pomona.
Step-by-step explanation:
First arranging our data of air quality index values for Pomona in ascending order, we get : 28, 42, 45, 48, 49, 50, 55, 58, 60.
- (a) Range is given by the formula :
Highest value in data - Lowest value in data = 60 - 28 = 32
(b) Interquartile rage = Third quartile - First quartile
=
=
observation in the data =
obs. { Because n = 9}
Therefore, = 42.
=
obs. = (3 x 2 ) =
obs = 50
So, Interquartile rage = 50 - 42 = 8.
2. (a) Sample mean formula = =
= 48.33
(b) Sample variance formula = where Xbar = Sample mean
= 92.75
(c) Sample standard deviation formula = =
= 9.63.
3. Given that a sample of air quality index readings for Anaheim has sample mean of 48.3, a sample variance of 136, and a sample standard deviation of 11.66.
We observe that sample mean of air quality index in Pomona is higher that that of Anaheim which indicates that the level of air pollution is higher in Pomona and there is more health concern here.
On the other hand, the variation in air quality index is higher in Anaheim than in Pomona as Anaheim has higher variance and standard deviation for air quality index which means that there are not much fluctuations in air quality index in Pomona.
Answer: 267.
Step-by-step explanation:
When there is no prior information for the population proportion, then the formula we use to find the sample size to estimate the confidence interval :
, where z* = Critical z-value and E + amrgin of error.
Let p = proportion of packages of ground beef sold at a particular store that have an actual fat content exceeding the fat content stated on the label.
Since , we have no prior information about p. so we use above formula
with E = 0.06 and critical value for 95% confidence =z* =1.96 [By z-table ] , we get
Hence, the required sample size is 267.