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Marianna [84]
3 years ago
7

four more than twice a number is greater than negative eighteen. Solve the inequality for the unknown number

Mathematics
1 answer:
Art [367]3 years ago
5 0

Answer:

4x>-18

Step-by-step explanation:

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Simplify √16/√11 in terms of surds<br>​
Alex_Xolod [135]

Answer:

4\times \sqrt{11}\div \(11)

Step-by-step explanation:

\sqrt{16}\div \sqrt{11}

\sqrt{16}\times \sqrt{11}\div \sqrt{11}\times \sqrt{11}

4\times \sqrt{11}\div \(11)  answer

8 0
3 years ago
I’m failing please help
jolli1 [7]

Answer:

Read below

<u>Non-proportional or Proportional:</u>

Non-proportional

B. is non-proportional

D. is non-proportional

E. is non-proportional

G. is non-proportional

H. is non- proportional

Proportional

A. is proportional

C. is proportional

F. is proportional

5 0
3 years ago
What percent of 600 is 750
Karo-lina-s [1.5K]
750 divided by 600 x 100 = 125%
7 0
3 years ago
Read 2 more answers
The width of a rectangle is (x-5) and the length is (x+2). What is the length and width of the rectangle if the area is 18 squar
Murrr4er [49]

Answer:

Length: 9

Width: 2

Step-by-step explanation:

Area = length × width

18 = (x - 5)(x + 2)

18 = x² - 5x + 2x - 10

x² - 3x - 28 = 0

x² - 7x + 4x - 28 = 0

x(x - 7) + 4(x - 7) = 0

(x - 7)(x + 4) = 0

x = 7, -4(not possible)

Length: 7+2 = 9

Width: 7-5 = 2

3 0
2 years ago
Read 2 more answers
A data set includes data from student evaluations of courses. The summary statistics are nequals83​, x overbarequals3.32​, sequa
Andrews [41]

Answer:

Hypothesis

Null hypothesis:\mu =3.50    

Alternative hypothesis:\mu \neq 3.50    

Statistic

t=\frac{3.32-3.50}{\frac{0.56}{\sqrt{83}}}=-2.928    

P value

The degrees of freedom are given by:

df=n-1=83-1=82

And the p value would be given by:

p_v =2*P(t_{(82)}    

Conclusion

Since the p value is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 3.5

Step-by-step explanation:

Information given

\bar X=3.32 represent the sample mean

s=0.56 represent the sample deviation

n=83 sample size    

\mu_o =3.5 represent the value to test

t would represent the statistic

p_v represent the p value

System of hypothesis

We want to verify if the true mean is equal to 3.5, the system of hypothesis are:    

Null hypothesis:\mu =3.50    

Alternative hypothesis:\mu \neq 3.50    

Statistic

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

Replacing we got:

t=\frac{3.32-3.50}{\frac{0.56}{\sqrt{83}}}=-2.928    

P value

The degrees of freedom are given by:

df=n-1=83-1=82

And the p value would be given by:

p_v =2*P(t_{(82)}    

Conclusion

Since the p value is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 3.5

8 0
2 years ago
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