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elena-14-01-66 [18.8K]
3 years ago
9

Find the equation of the line that is parallel to y = 4x + 1 and contains the point (1, 1).

Mathematics
2 answers:
n200080 [17]3 years ago
4 0

Answer:

y=4x+1

answer= y=4x

Step-by-step explanation:

y=4x+1

1=4(1)+1

1=5

azamat3 years ago
3 0

Answer:

4x-3

Step-by-step explanation:

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igor_vitrenko [27]

The roots are 1 +√7 and 1 -√7.

<h3>What is Quadratic equation?</h3>

A quadratic equation in the variable x is an equation of the form ax² + bx + c= 0, where a, b, c are real numbers, a≠0

Given equation:

y= x²+2x-6

First,

Half the coefficient of x and add and subtract the square of (b/2)

y= x²+2x-6+(1)²-(1)²

y= x²+2x+(1)² -6 -(1)²

y= (x+1)² -7

Now, equate y=0

(x+1)² -7 =0

(x+1)² = 7

x+1= ±√7

x=1 ±√7

Hence, the roots are 1 +√7 and 1 -√7.

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7 0
2 years ago
find the value of x2 values that separate the middle 90% from the rest of the distribution for 8 degrees of freedom
Anettt [7]

Answer:

With alpha 0.95 and 8 degrees of freedom χ²= 2.73

And with alpha 0.05 and 8 degrees of freedom χ²=15.51

Step-by-step explanation:

The significance level ∝ = 1- 0.9 = 0.1

But we need the area of the middle so we divide this significance level with 2

so that we get exactly the middle area .

Dividing 0.1/2= 0.05

So we will have two values for chi square

One with  0.9 + 0.05 = 0.95 alpha and one with 0.05 alpha . This is because the chi square is right tailed.

So with alpha 0.95 and 8 degrees of freedom χ²= 2.73

And with alpha 0.05 and 8 degrees of freedom χ²=15.51

This can be shown with a graph.

4 0
3 years ago
Solve the system by elimination <br> 2x+6y= -12 <br> 5x-5y= -10
kvv77 [185]
First thing you should do is reduce coefficients.

1st equation has all multiples of '2'. Divide by 2
---> x +3y = -6

2nd equation has multiples of 5. Divide by 5.
---> x - y = 2

Now elimination part is easier. 
Eliminate 'x' variable by subtracting 2nd equation from 1st.

   x + 3y = -6
-(x  - y = 2)
----------------------
       4y  = -8

Solve for 'y'
4y = -8

y = (-8)/4 = -2


Substitute value for 'y' back into 2nd equation:
x - (-2) = 2
x + 2 = 2
x = 0

Solution to system is:
x=0, y =-2

5 0
4 years ago
Read 2 more answers
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