The balanced chemical equation for the reaction is
<h3>6Cs(s) + 2CsNO₂(s) —> 4Cs₂O(s) + N₂(g) </h3>
From the question given above, we were told that:
solid cesium reacts with solid cesium nitrite to form solid cesium oxide and nitrogen gas.
The equation for the reaction can be written as follow:
Caesium => Cs
Caesium nitrite => CsNO₂
cesium oxide => Cs₂O
nitrogen gas => N₂
Caesium + Caesium nitrite —> Caesium oxide + Nitrogen gas
<h3>Cs + CsNO₂ —> Cs₂O + N₂</h3>
The above equation can be balance as follow:
Cs + CsNO₂ —> Cs₂O + N₂
There are 2 atoms of N on the right side and 1 atom on the left side. It can be balance by writing 2 before CsNO₂ as shown below:
Cs + 2CsNO₂ —> Cs₂O + N₂
There are 2 atoms of Cs on the right side and a total 3 atoms on the left side. It can be balance by writing 6 before Cs and 4 before Cs₂O as shown below:
6Cs(s) + 2CsNO₂(s) —> 4Cs₂O(s) + N₂(g)
Now the equation is balanced
Learn more: brainly.com/question/11502387
Explanation:
<em>(</em><em>P1V1</em><em>)</em><em>/</em><em>T1</em><em>=</em><em>(</em><em>P2V2</em><em>)</em><em>/</em><em>T2</em>
<em>(</em><em>1</em><em>5</em><em>X</em><em>5</em><em>)</em><em>/</em><em>2</em><em>9</em><em>7</em><em>=</em><em>(</em><em>p2x2</em><em>.</em><em>5</em><em>)</em><em>/</em><em>4</em><em>7</em><em>3</em>
<em>p2</em><em>=</em><em>47.78cmHg</em>
Answer:
The final pressure will double i.e it will be twice the initial pressure
Explanation:
T1 = T
T2 = 2T ( twice the original T)
P1 = P
P2 =?
Since the volume is constant,
P1/ T1 = P2 /T2
P/ T = P2 / 2T
Cross multiply
T x P2 = 2T x P
Divide both side by T
P2 = (2T x P) / T
P2 = 2P
Therefore, the final pressure will double i.e it will be twice the initial pressure
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