Answer:
The correct answer is b.
Explanation:
The quantum number n specifies the energetic level of the orbital, the first level being the one with the least energy. As n increases, the probability of finding the electron near the nucleus decreases and the orbital energy increases.
In the case of atoms with more than one electron, the quantum number l also determines the sublevel of energy in which an orbital is found, within a certain energy level. The value of l is designated by the letters s, p, d, and f.
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Inclined planes reduce the amount of effort needed to move an object, but increases the length of the ramp.
<u>Explanation:</u>
Mechanical advantage is the measure of amount of effort needed to move an object. The mechanical advantage can be calculated as the ratio of length of ramp to the height of ramp for an inclined plane.
As it is known that an object can be easily moved on an inclined plane than on a vertical plane, this is because, the inclined plane provides greater output force. But in that case, the effort required will be reduced with the cost of increasing the distance of the movement of object.
In other terms , the ramp's length of inclined planes has to get increased in order to reduce the amount of effort needed to move an object. This is because as the mechanical advantage has length of the ramp in the numerator, with the increase in numerator value or length value the mechanical advantage will also increase.
Answer:
![E=55mV](https://tex.z-dn.net/?f=E%3D55mV)
Explanation:
Hello,
Considering the given information, the new concentration of Na+inside will be (13.6 + 4) mM = 17.6 mM, and outside will be (150 + 0.04) mM = 150.04 mM due to the previous specified conditions.
Now, the recalculation of the Nerst potential at the supposed temperature of 25 °C (which is modifiable) is done via:
![E=\frac{RT}{zF} ln(\frac{C_{Na^+,outside}}{C_{Na^+,outside}} )\\\\E=\frac{8.314\frac{J}{mol*K}*298K}{1*9.65x10^4\frac{C}{mol} } *ln(\frac{150.04}{17.6} )=0.055V*\frac{1x10^3mV}{1V} \\E=55mV](https://tex.z-dn.net/?f=E%3D%5Cfrac%7BRT%7D%7BzF%7D%20ln%28%5Cfrac%7BC_%7BNa%5E%2B%2Coutside%7D%7D%7BC_%7BNa%5E%2B%2Coutside%7D%7D%20%29%5C%5C%5C%5CE%3D%5Cfrac%7B8.314%5Cfrac%7BJ%7D%7Bmol%2AK%7D%2A298K%7D%7B1%2A9.65x10%5E4%5Cfrac%7BC%7D%7Bmol%7D%20%7D%20%2Aln%28%5Cfrac%7B150.04%7D%7B17.6%7D%20%29%3D0.055V%2A%5Cfrac%7B1x10%5E3mV%7D%7B1V%7D%20%5C%5CE%3D55mV)
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