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3 years ago

7

a certain gas occupies 5 dm³ at 24 °C and 15 cm Hg. Calculate the pressure of the gas if the volume is halved and the temperatur

e is raised to 200°C.

1 answer:

Fantom [35]3 years ago

7 0

Explanation:

<em>(</em><em>P1V1</em><em>)</em><em>/</em><em>T1</em><em>=</em><em>(</em><em>P2V2</em><em>)</em><em>/</em><em>T2</em>

<em>(</em><em>1</em><em>5</em><em>X</em><em>5</em><em>)</em><em>/</em><em>2</em><em>9</em><em>7</em><em>=</em><em>(</em><em>p2x2</em><em>.</em><em>5</em><em>)</em><em>/</em><em>4</em><em>7</em><em>3</em>

<em>p2</em><em>=</em><em>47.78cmHg</em>

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<u>Answer:</u> The amount remained after 151 seconds are 0.041 moles

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Rate law expression for first order kinetics is given by the equation:

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4 years ago