All categories

3 years ago

What is 4/5% of 500 rounded to the nearest hundredth

Mathematics

1 answer:

elena-s [515]3 years ago

6 0

Answer: 4/5% of 500 rounded to the nearest hundredth is 400

Step-by-step explanation:

i would say to solve 4/5 and then put 500 as the denominator next to it then 5x100 is 500 then times 4 times 100 which is 400.

You might be interested in

Solve for m.<br><br> 3m+7/2=−2m+5/2<br> I will give brainleist

DiKsa [7]

M = -1/2 or m = 0.2.

8 0

3 years ago

The number of peach trees in the orchard is directly proportional to

My name is Ann [436]

Answer:

there was a difference between the 40 and 120 which was 80 so if there are 500 peach trees he would need to plant 580 because you add the difference to the total. The answer is 580 apple trees

Step-by-step explanation:

plz mark brainliest

6 0

3 years ago

List the following numbers in order from least to greatest 2.31, 2.13, 0.123, 3.12

dimulka [17.4K]

0.123, 2.13, 2.31, then 3.12. Hope this helps. :)

7 0

4 years ago

Read 2 more answers

Statistics professors believe the average number of headaches per semester for all students is more than 18. From a random sampl

kompoz [17]

Complete Question

Statistics professors believe the average number of headaches per semester for all students is more than 18. From a random sample of 15 students, the professors find the mean number of headaches is 19 and the standard deviation is 1.7. Assume the population distribution of number of headaches is normal.the correct conclusion at $\alpha =0.001$ is?

Answer:

There is no sufficient evidence to support the professor believe

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 18$

The sample size is $n = 15$

The sample mean is $\= x = 19$

The standard deviation is $\sigma = 1.7$

The level of significance is $\alpha = 0.001$

The null hypothesis is $H_o: \mu = 18$

The alternative hypothesis is $H_a : \mu > 18$

The critical value of the level of significance from the normal distribution table is

$Z_{\alpha } = 3.290527$

The test hypothesis is mathematically represented as

$t = \frac{\= x - \mu }{ \frac{\sigma}{ \sqrt{n} } }$

substituting values

$t = \frac{ 19 - 18}{ \frac{1.7}{ \sqrt{15} } }$

$t = 2.28$

Looking at the value of t and $Z_{\alpha }$ we can see that $t < Z_{\alpha }$ so we fail to reject the null hypothesis.

This mean that there is no sufficient evidence to support the professor believe

3 0

4 years ago

miguel is 5ft 10 inches tall On a sunny day he casts a shadow of 4ft 2 inches long. At the same time, a nearby electric tower ca

Alex787 [66]

Given:
Miguel's height:
Actual = 5 feet 10 inches
Shadow = 4 feet 2 inches

Tower's height
Actual = x
Shadow = 8 feet 9 inches

First, we need to convert the height into inches to avoid confusion.
1 foot = 12 inches.
Miguel:
5 ft x 12in/ft = 60 inches + 10 inches = 70 inches ACTUAL
4 ft x 12in/ft = 48 inches + 2 inches = 50 inches SHADOW

Tower:
8 ft x 12in/ft = 96 inches + 9 inches = 105 inches SHADOW

Ratio of Actual to shadow:
Miguel: 70 : 50
Tower: x : 105

70 : 50 = x : 105
70*105 = 50x
7350 = 50x
7350 / 50 = x
147 = x

Actual height of the tower is 147 inches or 12 feet 3 inches long.

To check:
Miguel : 70 / 50 = 1.40
Tower : 147 / 105 = 1.40

4 0

3 years ago

Read 2 more answers