Question

Questions 19 - 23. 23 is cut off a part so the second page is the rest of it.

Answer 1

20. H=5 because 5x5 equals 25
C=10 because 2+10=12
Y=10 3x10=30 , 30+10=40

Answer 2

19. Distributive property is multiplying everything outside of the parenthesis by everything in them!

Let's do it

2(3x + 4y)

We will multiply 2 by 3x and 2 by 4y

2 × 3x + 2 × 4y = ?

6x + 8y

20. Solving algebraically is using multiplication and division, addition and subtraction!

5h = 25

divide 25 by 5 to find h

h = 25/5

h = 5

2 + c = 12

subtract 2 from both sides

2 + c - 2 = 12 - 2

c = 12 -2

c = 10

3y + 10 = 40

We need to do subtraction and division for this one!

Let's subtract 10 from both sides

3y + 10 -10 = 40 - 10

3y = 30

Divide 30 by 3 to find y

y = 30/3

y = 10

CAN't SOLVE #21 BECAUSE OF LACK OF INFO

22. To find equivalent ratios, let's simplify them!

To simplify ratios, we need to find the highest common factors

a. 2:6

The highest common factor between 2 and 6 is 2, so let's divide both sides by 2

We get ... 1 : 3

b. The highest common factor between 12 and 30 is 6, so let's divide both sides by 6

We get ... 2 : 5

23. To find how many songs are played during a certain amount of time, all we need to do is multiply 12 (the amount of songs played in 1 hour) by however many hours they say!

This can be expressed like this

a. # of songs = 12 × h

Now let's use this expression to answer the next two parts of this question!

b. to find the "# of songs" played in 24 hours, all we need to do is multiply 12 by 24! 24 will be the "h" in our expression. h is the number of hours

Here's what it looks like using our expression we made

# of songs = 12 ( 24)

Solve using a calculator

# of songs = 288

c. To find how many hours it will take to play 60 songs, we will put it in place of the LEFT SIDE of the equation that says "# of songs"

Let's solve it now!

It looks like this ... 60 = 12h

Let's divide to find the number of hours!

60/12 = h

60/12 = 5

It will take 5 hours to play 60 songs!

Hope I helped! Message me or comment if you have any questions or concerns! :)