Answer:
Print.. is your answer...
This is what I come up with. I'm unclear what the 4th requirement means, so I've labeled it #unclear.
a { color : red; }
p:not(:first-child) { text-indent: 5%; }
div { background-color: aqua; }
#unclear { width: 50%; margin-left: 25%; margin-right: 25%; }
.links:link { font-size 24px; background-color: yellow; }
#first { text-transform: uppercase; font-style: italic; }
Answer:
if (pH<7.0){
neutral=0;
base=0;
acid=1;
}
else if (pH>7.0){
neutral=0;
base=1;
acid=0;
}
else if (pH==7.0){
neutral=1;
base=0;
acid=0;
}
Explanation:
As required by the question, if and else statements have been used to test the value of the pH and assign the apropriate values to the variables neutral, base and acid.
The code snippet below can be used to prompt the user to enter values for pH
<em>import java.util.Scanner;</em>
<em>public class pHTest {</em>
<em> public static void main(String[] args) {</em>
<em> Scanner scr = new Scanner(System.in);</em>
<em> System.out.println("Enter a value for the pH");</em>
<em> int neutral, base, acid;</em>
<em> double pH = scr.nextDouble();</em>
<em> if (pH<7.0){</em>
<em> neutral=0;</em>
<em> base=0;</em>
<em> acid=1;</em>
<em> }</em>
<em> else if (pH>7.0){</em>
<em> neutral=0;</em>
<em> base=1;</em>
<em> acid=0;</em>
<em> }</em>
<em> else if (pH==7.0){</em>
<em> neutral=1;</em>
<em> base=0;</em>
<em> acid=0;</em>
<em> }</em>
<em>} }</em>
Answer:
The Packets can be arrived out of an order from the Internet Protocol layer.
So, whenever the out of an order packets would be received then, it would be generated the duplicate ACK's, if we perform the re-transmission after the first duplicate ACK would be lead the senders to introduced too many redundant packets in the networks.
Explanation:
- All the bytes, in the Transmission Control Protocol connections, are the numbered, from the beginning at the randomly choose the initial sequence number (ISN).
- The SYN packets consumes the one sequence number, so the data will be actual and it begins at the ISN+1.
- The receivers ack's sequences the number x acknowledged the receipts of all the data bytes that is less than byte the number x.
