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3 years ago

Simply -5-3i/5-i It says I need more characters

Mathematics

1 answer:

Sindrei [870]3 years ago

7 0

Multiply by the conjugate and simplify.
−11/13 - 10i/13

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Guys please help me this is due tonight thanks

elena-s [515]

Answer:

the student in question bought 3 large notebooks and 3 small notebooks

Step-by-step explanation:

the easiest way to explain how to do this is by recognizing that the student bought $54 worth of notebooks- which is not divisible by 10 easily. that means, we should subtract 8 from 54 until we get a number that IS divisible

54 - 8 = 46 (one small notebook)

46 - 8 = 38 (two small notebooks)

3 8 - 8 = 30 (three small notebooks)

then, divide 30 by 10 to see how many large notebook the student bought.

30/10 = 3

the student in question bought 3 large notebooks and 3 small notebooks

4 0

3 years ago

Solve the following equation for 0° ≤ θ < 360°. Use the "^" key on the keyboard to indicate an exponent. For example, sin2x w

never [62]

Answer-

$\boxed{\boxed{x=90^{\circ},270^{\circ}}}$

Solution-

The given equation-

$\Rightarrow 2\sin^2 x-\cos^2 x-2=0$

$\sin^2 x+\cos^2 x=1\ \ \Rightarrow \cos^2 x=1-\sin^2 x$

Putting this,

$\Rightarrow 2\sin^2 x-(1-\sin^2 x)-2=0$

$\Rightarrow 2\sin^2 x-1+\sin^2 x-2=0$

$\Rightarrow 3\sin^2 x-3=0$

$\Rightarrow 3\sin^2 x=3$

$\Rightarrow \sin^2 x=1$

$\Rightarrow \sin x=\sqrt1$

$\Rightarrow \sin x=\pm 1$

$\Rightarrow \sin x=1,\ \sin x=-1$

$\Rightarrow x=\sin^{-1}(1),\ x=\sin^{-1}(-1)$

$\Rightarrow x=90^{\circ}+n360^{\circ},\ x=270^{\circ}+n360^{\circ}$

Where n=0, 1, 2, ......

As given 0° ≤ x < 360°, so putting n = 0

$\Rightarrow x=90^{\circ},\ x=270^{\circ}$

3 0

4 years ago

What is 3 1/2? A. -2/-7 B. -3 1/2 C. 3 1/3 D. -2/7

Stella [2.4K]

C 3 1/2
The lines in between the number means absolute value. This means that’s when the number is simplified it would become positive. Since 3 1/2 isn’t negative it would just stay the same

3 0

3 years ago

lyudmila [28]

${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

★ ∆ ABC is similar to ∆DEF

★ Area of triangle ABC = 64cm²

★ Area of triangle DEF = 121cm²

★ Side EF = 15.4 cm

${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

★ Side BC

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

Since, ∆ ABC is similar to ∆DEF

[ Whenever two traingles are similar, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. ]

$\therefore \tt \boxed{ \tt \dfrac{area( \triangle \: ABC )}{area( \triangle \: DEF)} = { \bigg(\frac{BC}{EF} \bigg)}^{2} }$