, write an expression should be used to determine the total number of points Amanda scored in Tuesday's game?

Simplify the ratio 35:50

RoseWind [281]

35:50 simplified is 7:10 because 5 goes into 35 7 times and 5 goes into 50 10 times.

3 0

3 years ago

170 ÷15 = 15 x ______ = 170

lions [1.4K]

the answer would be 11 1/3

6 0

3 years ago

The sum of a number t and 31

Radda [10]

It would be 31+t.
Unless there's more to this question.

6 0

3 years ago

Read 2 more answers

A train left for Houston, and 7 hours later, a car traveling 62 mph tried catching up to the train. After 4 hours, the car caugh

lana [24]

Answer: 22.55 mph

Step-by-step explanation:

Let the speed of the train be n

4 × 62 = 248 which is the distance travelled by the car in 4 hours and the train travelled in 11 hours

11 × n = 248

11n = 248

n = 248/11

n = 22.55mph

5 0

3 years ago

A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past

Vadim26 [7]

Answer:

We conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

Step-by-step explanation:

We are given that a particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past studies of this tire, the standard deviation is known to be 8000.

From the 28 tires surveyed, the mean lifespan was 46,500 miles with a standard deviation of 9800 miles.

Let $\mu$ = average miles for deluxe tires

So, Null Hypothesis, $H_0$ : $\mu \geq$ 50,000 miles {means that deluxe tire averages at least 50,000 miles before it needs to be replaced}

Alternate Hypothesis, $H_A$ : $\mu$ < 50,000 miles {means that deluxe tire averages less than 50,000 miles before it needs to be replaced}

The test statistics that will be used here is One-sample z test statistics as we know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean lifespan = 46,500 miles

$\sigma$ = population standard deviation = 8000 miles

n = sample of tires = 28

So, test statistics = $\frac{46,500-50,000}{\frac{8000}{\sqrt{28} } }$

= -2.315

The value of the test statistics is -2.315.

Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is less than the critical value of z as -2.315 < -1.6449, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

4 0

3 years ago