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const2013 [10]
3 years ago
5

Solve for the unknown value.

Mathematics
1 answer:
ahrayia [7]3 years ago
8 0

Answer:

77

Step-by-step explanation:

61+42=103

180-103=77

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Help me out on this one i will give u brainlyiest
nexus9112 [7]

Answer:

<h2>12 4/8</h2>

Step-by-step explanation:

1. First step

ADD

7+4=11

7+5=12

so

11\frac{12}{8}

2. Second step

Now simplify

11 12/8 = 12 4/8 = 12 1/2

----------------------------------------------------------------------------------------------------------

Thanks!

Answered by: FieryAnswererGT

#learnwithbrainly

Want to thank me? JUST MARK ME BRAINLIEST! So simple!

5 0
2 years ago
marc bought a bike for $800 in the year 2002 . its value depreciates by 6% per year . what was the value of bike in 2015 ? round
Anna007 [38]

Answer:

176

Step-by-step explanation:

800 × 0.06 (6%÷100= 0.06) = 48

48 × 13 (2015 - 2002 = 13) = 624

800-624 = 176

6 0
3 years ago
Solve the equation to get the value y
tia_tia [17]

Answer:

y=11

x=-4

Step-by-step explanation:

y =-x+7

2x-5y=-7

insert the first equation into the second like so...

2x+5x-35=-7

Now rearrange...

2x+5x=-7+35

Now solve...

7x=-28

x=-4

Now incert x in any equation...

y=4+7

y=11

5 0
2 years ago
Read 2 more answers
Suppose a certain religious university has a ratio of approximately 90 males to 125 females enrolled as a students. If he curren
Nitella [24]
How many males and how many females would there be if the total enrollment is 15000?

Ratio is 

  90 males      15000 - x
  ------------- = ---------------
   125 fem              x

Then 90x = 1875000 - 125x, or 215x = 1875000

                                                      x = approx 8720 females
                       and 15000-8720, or 6279 males

If every male finds a dance partner, that would leave (8720-6279) females, or 2440, without dance partners.  ;(

Check:  is the male:female ratio near 90:125?

Is 6279:8720 approx equal to 90:125?

Yes.  0.72 (approx) = 0.72 (approx).
7 0
3 years ago
Which statement is true about the graphed function?
yarga [219]

Answer: Choice D)

F(x) > 0 over the inverval (-infinity, -4)

Translation: The y or f(x) values are positive whenever x < -4.

========================================================

Further Explanation:

Recall that y = f(x), so if we say something like f(x) < 0 then we mean y < 0. Choice A is false because points on the curve to the left of x = -4 have positive y coordinates. Similar reasoning applies to choice B as well.

Choice C is false because while the interval (-infinity, -4) is above the x axis, the portion from x = -4 to x = -3 is below the x axis.

Choice D is true because everything to the left of x = -4 is above the x axis. Pick any point on the blue curve that is to the left of x = -4. This point will be above the horizontal x axis. Keep in mind that the parenthesis notation attached to the -4 means we dont include -4 as part of the interval.

4 0
3 years ago
Read 2 more answers
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