1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).
2. Use formula to find the distance from point to the line Ax+By+C=0.
The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:
.
3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.
Answer: .
Answer
-19
Step-by-step explanation:
AS WE NEED TO FIND THE DIFF SO -8-11=-19
(553-265)/48=6
6 hours spent repairing the car
Give me an operation like the one you are talki ng about and I can solve it
Multiply the numbers: 3 x 2=6 = 6x + 5 - 12x - 2 x 149x
Next Multiply the numbers 149 x 2 = 298
Then, Group like terms, =-6x-12x-298x+5
Add similar elements -6x-12x-298x=-316x,
and you get -316x+5!