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kykrilka [37]
2 years ago
11

Two points are g phedo the comdinate plane.

Mathematics
1 answer:
lozanna [386]2 years ago
7 0

Answer:

b

Step-by-step explanation:

yp

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Two sides of a triangle are 15 mm and 10 mm. The perimeter of the triangle is 35 mm. What's the third side?
grigory [225]
35mm-10mm-15mm=10mm
The third side is therefore 10mm in length
4 0
3 years ago
Your model train has one engine and eight train cars. Find the total number of ways you can arrange the train.
baherus [9]
The answer is five! Don't tell me how I got that because my sister did the problem 2 minutes ago because I told her this question! Hope this help!
4 0
3 years ago
Let U = {1, 2, 3, 4, 5, 6, 7}, A= {1, 3, 4, 6}, and B= {3, 5, 6}. Find the set A’ U B’
Art [367]

Answer:

Step-by-step explanation:

A'={2,5,7}

B'={1,2,4,7}

A'UB'={1,2,4,5,7}

8 0
3 years ago
Supposed five plain hamburgers cost the same as three super burgers. Also suppose that one super burger cost $.30 more than one
noname [10]

Answer:

1 plain = $0.75; 1 cheese = $0.95; 1 super = $1.25

Step-by-step explanation:

We have three conditions

(1) 5P = 3S

(2)  S = C + 0.30

(3)  P = C – 0.20                           Substitute (3) into (1)

=====

(4)   5(C – 0.20) = 3S                   Substitute (2) into (4)

      5(C – 0.20) = 3(C + 0.30)     Remove parentheses

         5C – 1.00 = 3C + 0.90       Add 1.00 to each side

                    5C = 3C + 1.90        Subtract 3C from each side

                    2C = 1.90                 Divide each side by 2

                      C = $0.95              Substitute C into Equation (2)

=====

                      S = 0.95 + 0.30

                      S = $1.25               Substitute C into Equation (3)

=====

                     P = 0.95 – 0.20

                    P = $0.75

1 plain = $0.75; 1 cheese = $0.95; 1 super = $1.25

3 0
3 years ago
In each of the following ,make y the subject and hence find the value of y when a=2, b=3 ,and c=4.
zvonat [6]

Part i


\dfrac{2a-7}{6y} = \dfrac{3b-5}{2c}


y = \dfrac{ 2c(2a-7)}{6(3b-5)} = \dfrac{c(2a-7)}{9b-15}


Substituting,

y = \dfrac{4(2(2)-7)}{9(3)-15} = \dfrac{ -12}{12} = -1


Answer: -1


Part ii


I'm not sure that one's typed in correctly but I'll solve it as written.


3-34y + 2a = \dfrac{3b-5}{2c + 1}


34y  = 3+2a-\dfrac{3b-5}{2c + 1}


y = \frac 1 {34}\left(3+2a-\dfrac{3b-5}{2c + 1} \right)


We're not asked to simplify it so I wont. Substituting,


y = \frac 1 {34}\left(3+2(2)-\dfrac{3(3)-5}{2(4) + 1} \right) = \frac 1 {34}(7-4/9) = \dfrac{59}{306}


Answer: 59/306



3 0
3 years ago
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