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3 years ago

Plz help me figure out what -5(6+x) is

Mathematics

2 answers:

Lina20 [59]3 years ago

7 0

The answer is -30-5x

KIM [24]3 years ago

4 0

Use distribution
this expression will simplify to:
-30-5x

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PLEASE help! this is so difficult! i literally cannot solve it to save my effing life.

jeka57 [31]

For the first question

The image grew bigger the new triangle is bigger than the original one

The scale factor is 3 by finding the length of

CA prime divided by Regular CA

8 0

3 years ago

Conti. 7-10 thanks a lot! unhelpful answers will be deleted.

Marysya12 [62]

Answers:

10. b. $\displaystyle 13$

9. b. $\displaystyle 20$

8. a. $\displaystyle 33$

7. a. $\displaystyle 25°$

Step-by-step explanations:

10. Both segments are considered congruent, so turn both expressions into an equation:

$\displaystyle 3x - 5 = x + 7 \hookrightarrow \frac{-12}{-2} = \frac{-2x}{-2} \\ \\ 6 = x$

Plug this back into the equation to get $\displaystyle 13$ on both sides.

9. All edges in a square obtain congruent right angles and edges, so set $\displaystyle 45$ equivalent to the given expression:

$\displaystyle 45 = 2x + 5 \hookrightarrow \frac{40}{2} = \frac{2x}{2} \\ \\ \boxed{20 = x}$

8. Both angles are considered supplementary, so turn both expressions into an equation and set it to one hundred eighty degrees:

$\displaystyle 180 = (4x - 15)° + (x + 30)° \hookrightarrow 180° = (15 + 5x)° \hookrightarrow \frac{165}{5} = \frac{5x}{5} \\ \\ \boxed{33 = x}$

7. In this rectangle, segment EO is a segment bisectour, making these angles Complementary Angles. Therefore, set an equation up to find its complement:

$\displaystyle 90° = 65° + m\angle{VOE} \\ \\ \boxed{25° = m\angle{VOE}}$

I am joyous to assist you at any time.

3 0

2 years ago

Determine forms of exponential expressions please help

Irina-Kira [14]

Answer:

(36^t) / (6^(t^2)) is nonequivalent

(6^(t^2)) / (36^t) is equivalent

(6^(t^2)) * 36^t is nonequivalent

Step-by-step explanation:

We can use the exponential quotient law for this problem.

a^x / a^y = a^x - y

(6^(t^2)) / (6^2t) = (6^(t^2)) / (36^t)

4 0

2 years ago

When Harper commutes to work, the amount of time it takes her to arrive is normally distributed with a mean of 24 minutes and a

Korvikt [17]

Answer:

$\mu -2\sigma = 24-2*3= 18$

$\mu -2\sigma = 24+2*3= 30$

So then we can conclude that we expect the middle 95% of the values within 18 and 30 minutes for this case

Step-by-step explanation:

For this case we can define the random variable X as the amount of time it takes her to arrive to work and we know that the distribution for X is given by:

$X \sim N(\mu = 24, \sigma =3)$

And we want to use the empirical rule to estimate the middle 95% of her commute times. And the empirical rule states that we have 68% of the values within one deviation from the mean, 95% of the values within two deviations from the mean and 99.7 % of the values within 3 deviations from the mean. And we can find the limits on this way:

$\mu -2\sigma = 24-2*3= 18$

$\mu -2\sigma = 24+2*3= 30$

So then we can conclude that we expect the middle 95% of the values within 18 and 30 minutes for this case

7 0

3 years ago

Hi can anyone do this for me please do it on a piece of paper

Vsevolod [243]

9514 1404 393

Answer:

see attached

Step-by-step explanation:

We don't know the drivers' names or when or where they started. We have made the assumption that the second equation pertains to Kylie.

Each line is plotted with the appropriate slope and y-intercept. The slope is the coefficient of x, and represents the "rise" for each unit of "run" to the right.

8 0

3 years ago