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3 years ago

What is the answer to 4 ⋅ (−6)

Mathematics

1 answer:

olganol [36]3 years ago

7 0

Answer:

-24

Step-by-step explanation:

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Find the range for these numbers. 12, 9, 24, 24, 37, 18, 9, 6, 24

svet-max [94.6K]

6, 9, 9, 12, 18, 24, 24, 24, 37

37-6= 31

5 0

3 years ago

Solve equation <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bk-4%7D%7B3%7D%20%3D%203" id="TexFormula1" title="\frac{k-4}{

3241004551 [841]

k-4/3= 3

Mutiply both sides by 3 .

(3)(k-4/3)= (3)(3)

Cross out 3 and 3 , divide by 3 and then becomes k-4= 9

Move -4 to the other side

Sign changes from -4 to +4

k-4+4= 9+4

k= 13

Answer: k= 13

6 0

3 years ago

What is the area of the polygon? A: 1,140 2 B: 1,620 2 C: 2,052 2 D: 2,220 2

PtichkaEL [24]

Answer:

B: 1620cm2

Step-by-step explanation:

16×15×2+30×20

6 0

3 years ago

Read 2 more answers

Help me here please.. .

Harman [31]

6x^2 is the answer. thanks for asking it.

6 0

4 years ago

You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o

Aleksandr [31]

Answer:

Therefore the circumference of the circle is $=\frac{20\pi}{4+\pi}$

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

$\Rightarrow s=\frac{10-\pi r}{2}$

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

$A=\pi r^2+ (\frac{10-\pi r}{2})^2$

$\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2$

$\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}$

$\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25$

For maximum or minimum $\frac{dA}{dr}=0$

Differentiating with respect to r

$\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi$

Again differentiating with respect to r

$\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}$ > 0

For maximum or minimum

$\frac{dA}{dr}=0$

$\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0$

$\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}$

$\Rightarrow r=\frac{10}{4+\pi}$

$\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0$

Therefore at $r=\frac{10}{4+\pi}$ , A is minimum.

Therefore the circumference of the circle is

$=2 \pi \frac{10}{4+\pi}$

$=\frac{20\pi}{4+\pi}$

4 0

3 years ago