The question is incomplete as it lacks the multiple options. The multiple option are as follows;
Careful monitoring for level of consciousness and resolution of hypoglycemia
.
IV infusion of 50% dextrose and water solution
.
Administration of subcutaneous glucagon
Administration of 15 to 20 g of glucose in a concentrated carbohydrate source
Answer:
Administration of 15 to 20 g of glucose in a concentrated carbohydrate source.
Explanation:
The insulin and glucagon hormone maintains the blood glucose level in the humans. In case of Type I diabetes a little amount or no amount of insulin is made by the pancreas.
The wife of a man has caused insulin error that creates hypoglycemic condition means the individual has low blood glucose level. The intake of carbohydrates can increase his blood glucose level. The wife should give 15 to 20 g of glucose to make the conditions normal.
Thus, the answer is option (4).
Answer and Explanation:
Running or jogging comes under the category of aerobic training/exercise. By definition, aerobic exercise means that the person is training her/his body in the presence of excessive oxygen. So, metabolically speaking, the person is relying on availability of oxygen to carry out metabolism which is mainly about production/supply of energy (ATP) by the breakdown of food in the presence of oxygen. This process is also known as cellular respiration. So, if a person is doing aerobic exercise (running), s/he needs more energy to keep doing the exercise. Typically, aerobic exercise produce more energy (32 molecules of ATP) as compared to anaerobic process (2 molecules of ATP) per reaction run. Thus, In the process of aerobic exercise, the lungs will respire faster to allow more diffusion of oxygen in the blood. Then, this oxygen will be transported to all body by heart pumping and then oxygen enters the cells. Once oxygen is entered, it acts as terminal electron acceptor in a process known as oxidative phosphorylation. This process takes plance in the mitochondria and produces 32 molecules of ATP per reaction.
B. meiosis produces cells that are used in reproduction.
Answer:
The result of cross two squashes with yellow seeds is an offspring of squash with green seeds -dominant caracter- heterozygous and yellow seeds squashes in a genotype proportion 1:2:1 and phenotype proportion 3:1
Explanation:
The cross of two heterozygous individuals for a characteristic results in an offspring that will have both characteristics in pure and heterozygous form. It is a cross monohybrid which complies with the principle of independent segregation exposed by Mendel.
For the characteristic "seed color" the green color would be G and yellow represented as g.
At the cross of two heterozygous squashs:
- Parents: Gg X Gg
- <u>Punnett's Square</u>:
Alleles G g
G GG Gg
g Gg gg
Offspring:
- A pumpkin of green seeds GG (25%)
- Two pumpkins of green heterozygous seeds Gg (50%)
- One pumpkin of yellow seeds gg (25%)
Genotype proportion 1:2:1
Phenotype proportion 3:1
Answer:
so they can fly obviously
