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2 years ago

Where does each go (A,B,C,D,E,F,G,H,I,J)?

Mathematics

1 answer:

disa [49]2 years ago

8 0

Answer:

for polynomial 4x^2-2x+14, degree=2/ special name=trinomial

for 22(x^2)(y^2)-2x+14, degree=2/ special name= trinomial

for 7x+2, degree=2/ binomial

for 2(x^3)-6xy+13xy^2, degree=3/ trinomial

for a^3-8, degree=3/ binomial

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How many time larger is 9x10^-8 than 3x10^-12

kkurt [141]

Step-by-step explanation:

$\frac{9 \times 10 {}^{ - 8} }{3 \times 10 {}^{ - 12} }$

Apply Quoteint of Powers. Divide the intergers. serpately.

Note that Quotient of Powers is

$\frac{a {}^{x} }{a {}^{y} } = a {}^{x - y}$

So the answer is

$3 \times 10 {}^{ - 8 + 12} = 3 \times 10 {}^{4}$

The answer is

$3 \times 10 {}^{4}$

$30000$

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2 years ago

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Answer:

Step-by-step explanation:

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1 year ago

Keisha makes a large sandwich for a family picnic. She takes 1/2 of the sandwich to the picnic.At the picnic, her family eats 3/

Vesna [10]

1/2 - 3/8 = 4/8 - 3/8 = 1/8
you have to find a common denominator before you can subtract. in this case it is 8

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2 years ago

What's the power of a power

ahrayia [7]

<span>The power of a number says how many times to use the number in a multiplication. It is written as a small number to the right and above the base number.</span>

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2 years ago

An experiment is completed where a coin is flipped and a six-sided die (singular for dice) is rolled. The outcomes from the expe

victus00 [196]

Answer:

1) $16\frac{2}{3}$ % or 20%

Step-by-step explanation:

Given that:

An experiment which is carried out by flipping a coin and rolling six sided die.

The outcomes can be:

{H1, H2, H3, H5, H6, T1, T1, T2, T3, T5}

As per question statement:

Number of outcomes having tails and an odd number greater than one is 2 (i.e. T3 and T5)

Total number of outcomes here is 10.

Therefore, to find the percentage, we use the following formula:

$\dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\times 100$

$\Rightarrow \dfrac{2}{10}\times 100 = 20\%$

As per question statement, the answer is 20%.

If we consider all the outcomes, i.e.

{H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6}

Total number of outcomes = 12

The percentage will come out be :

$\Rightarrow \dfrac{2}{12}\times 100 = 16\frac{2}{3}\%$

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2 years ago