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kotegsom [21]
2 years ago
13

Evaluate the expression -3 ⅓ (-2 ⅕)

Mathematics
1 answer:
Dahasolnce [82]2 years ago
3 0

Answer:

7.3...

10/3×11/5= 110/15

110/15=22/3

22/3=7.3...

thus the answer is 7.3...

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The bank does not charge a fee for cashing checks as long as members keep a balance, b, of at least $500 in their checking accou
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b  ≥  500

Step-by-step explanation:

since the balance has to be at least 500, b has to be grater than or equal to 500, so b ≥ 500

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Robin was just hired at Groceries & More as a cashler. They pay her $12 an hour. She works 20 hours a week and is going to s
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5 weeks

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We know that she works at a rate of $12 an hour, she also works 20 hours a week.

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1 year ago
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2 years ago
Use this diagram to find the required measures. 1 = 30°, 2 = 30°, 3 =
crimeas [40]

Answer:

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Step-by-step explanation:

7 0
2 years ago
3. (05.06 MC)
AveGali [126]

Answer:

Step-by-step explanation:

y > 3x + 10

y < -3x - 1

<h3> Part A:</h3>

You'd graph the given systems of linear inequalities the same way as you graph the linear equations.  

To graph y > 3x + 10, plot the y-intercept, (0, 10), then use the slope, m = 3 (rise 3, run 1), to plot other points on the graph.  Use a dashed line (because of the ">" symbol).  

Follow the same steps for the other linear inequality. Plot the y-intercept, (0, -1), then use the slope, m = -3 (down 3, run 1) to plot other points. Use a dashed line (because of the "<" symbol).  

Pick a test point on either side of the boundary line and plug it into the original problem.  This will help determine which side of the boundary line is the solution.  Plug in a test point that is not on the boundary line.

Use the point of origin, (0, 0) as the test point. Plug in these values into the given systems of linear inequalities to see whether it will provide a true statement.  

y > 3x + 10

0 > 3(0) + 10

0 > 0 + 10

0 > 10 (False statement).  

y < -3x - 1

0 < -3(0) - 1

0 < 0 - 1

0 < -1 (false statement).  

Since the point of origin provided a false statement to the given systems of linear inequalities, you must shade the half-plane region where it doesn't contain the test point.  

<h3>Part B: </h3>

You'll do the same process as what I've done for the test point. Plug in the values of (8, 10) into the given systems of linear inequalities. If it provides a false statement, then it means that it is not a solution to the system.  

y > 3x + 10

10 > 3(8) + 10

10 > 24 + 10

10 > 34 (False statement).  

y < -3x - 1  

10 < -3(8) - 1

10 < -24 - 1

10 < -25 (false statement).  

Therefore, (8, 10) is not a solution to the system.    

8 0
2 years ago
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