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Eduardwww [97]
3 years ago
9

What is the perimeter of a rectangle with a length of 12 inches and a width of 5.76 inches

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
6 0
Perimeter = 35.52
12+12+5.76+5.76=35.52
ludmilkaskok [199]3 years ago
3 1

Answer:

35.52 inches

Step-by-step explanation:

Perimeter (of a rectangle) = 2 * length + 2 * width

2 * 12 + 2 * 5.76 = 35.52

Perimeter of the rectangle is 35.52 inches.

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One canned juice drink is 20% orange juice; another is 10% orange juice l. How many liters of each should be mixed together in o
Anni [7]

Answer:

There is not enough information to answer, you did not say measurements of both drinks.

Step-by-step explanation:

8 0
2 years ago
Rewrite the following equation in slope-inte
Nonamiya [84]

Answer:

y = 13x + 86

Step-by-step explanation:

y−8 =13(x+6); distribute the 13

y - 8 = 13x + 78; now add 8 to both sides

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7 0
2 years ago
Determine the mass of a solid steel ball that has a diameter of 10 cm. The density of pure steel is 8.09 g/cm3
Basile [38]

Answer:

<em>The mass of the steel ball is 4,235.9 gr</em>

Step-by-step explanation:

<u>Density</u>

The density ρ of a substance is a measure of its mass per unit volume:

\displaystyle \rho=\frac{m}{V}

If the density and the volume are given, the mass can be calculated by solving the above formula for m:

m=\rho.V

We know the density of pure steel ρ=8.09 gr/cm3 and the diameter of a solid steel ball d=10 cm.

We need to calculate the volume of the sphere:

The volume of a sphere of radius r is given by:

\displaystyle V=\frac{4}{3}\cdot \pi\cdot r^3

The radius is half the diameter: r= 10/2 = 5 cm. Thus:

\displaystyle V=\frac{4}{3}\cdot \pi\cdot 5^3

Calculating:

V=523.6\ cm^3

The mass is:

m=8.09 gr/cm^3 \cdot 523.6\ cm^3

m=4,235.9 gr

The mass of the steel ball is 4,235.9 gr

4 0
2 years ago
2 3/4 divided by 1 7/8? Type the quotient in the simplest form
kompoz [17]

Reduce the expression, if possible, by canceling the common factors.

Exact Form: 22/15

Decimal Form: 1.46

Mixed Number Form: 1/715

7 0
2 years ago
Please help me ^^ This is due tomorrow
saveliy_v [14]
The answer is 5.

You just plug whatever number is in the f(?) part in for x!
7 0
3 years ago
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