PLEASE. HELP.

Mathematics

1 answer:

jekas [21]3 years ago

6 0

I think the answer is A I’m not sure tho

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Graph y-intercept x-intercept vertex y=x^2+4x-5

Strike441 [17]

Answer:

y intercept - (0,-5)

x intercepts - (-5,0) and (1,0)

vertex (-2,-9)

Step-by-step explanation:

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2 years ago

Whats the decimal that is equivalent to 1/15

riadik2000 [5.3K]

0.0666666666 is the answer. Hope this helps! Please mark Brainliest!

-Belle

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3 years ago

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The probability of drawing a quarter from a bag of coins is 4/5. What is the probability of drawing a coin that is not a quarter

elixir [45]

The sum of probability for an event happening and not happening must be equal to 1 because there is a 100% chance that one or the other will occur.

So the probability on not drawing a quarter:

P(!Q)=1-4/5

P(!Q)=5/5-4/5

P(!Q)=1/5

As a percentage:

p/100=1/5

p=100/5

p=20%

8 0

2 years ago

Indicate the method you would use to prove the two 's . If no method applies, enter "none".SSS

balu736 [363]

I hope this helps you

3 same angle one same side

ASA

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2 years ago

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On a coordinate plane, a shape is plotted with vertices of (3, 1), (0, 4), (3, 7), and (6, 4). what is the area of the shape if

QveST [7]

Let
A (3, 1)
B (0, 4)
C(3, 7)
D (6, 4)

step 1
find the distance AB
d=√[(y2-y1)²+(x2-x1)²]------> dAB=√[(4-1)²+(0-3)²]-----> dAB=√18 cm

step 2
find the distance CD
d=√[(y2-y1)²+(x2-x1)²]------> dCD=√[(4-7)²+(6-3)²]-----> dCD=√18 cm

step 3
find the distance AD
d=√[(y2-y1)²+(x2-x1)²]------> dAD=√[(4-1)²+(6-3)²]-----> dAD=√18 cm

step 4
find the distance BC
d=√[(y2-y1)²+(x2-x1)²]------> dBC=√[(7-4)²+(3-0)²]-----> dBC=√18 cm

step 5
find slope AB and CD
m=(y2-y1)/(x2-x1)
mAB=-1
mCD=-1
AB and CD are parallel and AB=CD

step 6
find slope AD and BC
m=(y2-y1)/(x2-x1)
mAD=1
mBC=1
AD and BC are parallel and AD=BC
and
AB and AD are perpendicular
BC and CD are perpendicular

therefore
the shape is a square wit length side √18 cm

area of a square=b²
b is the length side of a square
area of a square=(√18)²------> 18 cm²

the answer is
18 cm²

see the attached figure

6 0

3 years ago