To find the quotient of 3 divided by one-sixth, multiply 3 by
2 answers:
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For this case we have:
Let a function of the form
By definition, to graph , where
, we must move the graph of f (x), h units to the left.
We observe that the red graph has the same form as the black graph, but it is displaced "h" units to the left.
It is observed that
So, if the black graph is given by, the red graph is given by:
Answer:
Option A
Answer:
Step-by-step explanation:
first problem:
3 is a solution to x^2=9, so to a, b, c and d
second problem
-2 is a solution to:
a, b, c and d because (-2)^2=4, 4=4, b) 5*(-2)^2=5*4=20 and so on
basically to all choices
the third, solve the equations:
x^2=1, =
, x=1
x^2=81 sqrtx^2=sqrt81, x=+and -9
4x^2=1 divide by 4 , x^2=1/4, x=+&- 1/2 (plus si minus 1/2, amindoua solutiile sint valabile)
3x^2=75, we divide by 3, we get x^2=25, x=+&-5
49x^2=121 , x=+and- 11/7
25x^2=225 divide by 25, x^2=9, x =+and - 3
36x^2=144 we divide by 36, we get x^2=4, x = +and- 2
x^2-0.25=0 x^2=0.25, x=+and - 1/2
2x^2-0.32=0 , 2x^2=0.32, x^2=0.16 ( i divided by 2) , x=+and- 2/5
4x^2=0.04, divide by 4, x^2=0.01, x=+and - 0.1
3x^2=10.8, divide by 3, x^2=3.6, x=+and - 1,89
for the : determinati solutiile ecuatiilor
a) (x-1)^2=49, do the quadratic, you get x=8 and -6
due to the length of this page, i cant explain every step
b) (2x+1)^2=81, you get x= 4 and -5
c)(3x-1)^2=121, do the quadratic, x=- 10/3 and +4
d) 3(x-3)^2=48, we divide by 3 first , (x-3)^2=16, we get x=7 and -1
e)5(x+2)^2=45 we divide by 5, (x+2)^2=9, x=+1and -5
f) 7(2x-1)^2=175 we divide by 7 and we have (2x-1)^2=25 x=+3 and -2
Determine x belong to R
a) 1/9 x^2=16, we multiply 9*16=144, x^2=144, x=+and - 12
1/100x^2-1/64=0, or 1/100 x^2=1/64, x=+and - 5/4
1/25 x^2=0.49, x^2=0.49*25=12.25, x=+ and - 7/2