M< 6 = m< 7 (vertical angles)
11x + 8 = <span>12x – 4
12x - 11x = 8 + 4
x = 12
so
m< 6 = </span>11x + 8
m< 6 = 11(12) + 8
m< 6 = 132 + 8
m< 6 = 140
m<4 = 180 - m<6
m<4 = 180 - 140
m<4 = 40
answer
<span>m<4 = 40</span>
Us Photomath boy 69+420=)9
The line from the point to its reflection should be perpendicular.If we imagine a line from (5,7) to (2,2), it would have a slope of (2-7)/(2-5) = 5/3.
For that line to be perpendicular to y=-2/5x+6, their slopes should be each other's negative reciprocals.
-2/5 negative reciprocal is 5/2, which is not equal to our calculated 5/3, so (2,2) cannot be the reflected point. Evan was wrong.
Q1-74: AB have slope 6/5, C has -5/6, D 6/5, E -5/6 again.
It should just be 2x-5= 125
Then add 5 to both sides
2x= 130
Divide by 2
X= 65
Answer:
10
Step-by-step explanation:
