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Anarel [89]
3 years ago
11

Alice has eight stars gets a new one each week

Mathematics
2 answers:
riadik2000 [5.3K]3 years ago
6 0
6 weeks it takes 6 weeks for them to have the same amount
Stels [109]3 years ago
5 0
Answer: it takes 6 weeks for them to have the same amount of stars (14 and 14)
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All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
3 years ago
Only t circled ones somebody plz help I am gonna get a 0 plz help I will give you brainleist
Vikki [24]

Step-by-step explanation:

1) A number <em>m</em> is at least four

<em>m ≥ 4  ['at least' = ≥ symbol]</em>

<em />

2) 4x  ≤ 20x; x=2

4(2) ≤ 20(2)

8 ≤ 40

[Im not sure if this is a solution or and inequality :/ ]

3)  x < 5

--> On the line, draw the number 0, and the number five. 'x < 5' also means 'x is less that five.' So, draw a dot over the line before 5, and make an arrow going to the left of the page,

<-----------------------------------o   5

<---|---|---|---|---|---|---|---|---|---|---|---|---|---|--->

                          0

Hopefully this helps! :)

4 0
3 years ago
Find f(2) if f(x) = (x + 1)2.<br> 9<br> 6<br> 5
zhannawk [14.2K]
6 just trust me bro I’m a major in math
8 0
3 years ago
ILL GIVE BRAINELST
Angelina_Jolie [31]

Answer: number 3 4 5

Step-by-step explanation:hope this helps!

5 0
2 years ago
The mathematics department of a college has 6 male professors, 9 female professors, 5 male teaching assistants, and 6 female tea
Hitman42 [59]

Given:

6 male professores

9 female professores

5 male teaching assistants

6 female teaching assistants

Sol:.

N(A\text{ or B)=N(A)+N(B)-N(A and B)}

N (professors)

\begin{gathered} =6+9 \\ =15 \end{gathered}

N(Male)

\begin{gathered} =6+5 \\ =11 \end{gathered}

N(professors and male)

=6

N(professors OR male) = N(professors) + N(males) -N(professor OR male)

\begin{gathered} N(\text{ Professors OR male)=15+11-6} \\ =20 \end{gathered}

N(People to choose from)

\begin{gathered} =6+9+5+6 \\ =26 \end{gathered}

Then probablitiy is:

\begin{gathered} =\frac{20}{26} \\ =\frac{10}{13} \end{gathered}

Then the probability is 10/13

6 0
1 year ago
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