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Lera25 [3.4K]
2 years ago
8

PLS HELPPP!!! I NEED THIS ANSWER

Mathematics
1 answer:
andriy [413]2 years ago
5 0

Answer:

use photo math

Step-by-step explanation:

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I have a question here. ​
taurus [48]

9514 1404 393

Answer:

  P(F|A) = 35%

Step-by-step explanation:

P(F|A) = P(F&A)/P(A) = 7%/20% = 0.35

P(F|A) = 35%

_____

The given numbers will let you fill in a table for all of the categories of workers. However, it turns out this question can be answered using only the numbers given in the problem statement.

6 0
2 years ago
identify the amplitude and period of the function then graph the function and describe the graph of G as a transformation of the
mrs_skeptik [129]

Given the function:

g(x)=cos4x

Let's find the amplitude and period of the function.

Apply the general cosine function:

f(x)=Acos(bx+c)+d

Where A is the amplitude.

Comparing both functions, we have:

A = 1

b = 4

Hence, we have:

Amplitude, A = 1

To find the period, we have:

\frac{2\pi}{b}=\frac{2\pi}{4}=\frac{\pi}{2}

Therefore, the period is = π/2

The graph of the function is shown below:

The parent function of the given function is:

f(x)=cosx

Let's describe the transformation..

Apply the transformation rules for function.

We have:

The transformation that occured from f(x) = cosx to g(x) = cos4x using the rules of transformation can be said to be a horizontal compression.

ANSWER:

Amplitude = 1

Period = π/2

Transformation = horizontal compression.

8 0
9 months ago
A telecommunication company has 7 satellites, two of which are sending a week signal. If two are picked at random without replac
Setler [38]
2/7 is the probability that the first satellite sends a weak signal. That leaves 6, one of which sends a weak signal. So the probability that the second also sends a weak signal is 1/6. Combine these and we get 2/7×1/6=1/21.
5 0
3 years ago
Ignoring leap days, the days of the year can be numbered 1 to 365. Assume that birthdays are equally likely to fall on any day o
faust18 [17]

Answer:

Follows are the solution to the given question:

Step-by-step explanation:

They can count the days of the year 1 to 365. The random project consists of drawing a sample of n objects from D where elements are n people's birth in a group but instead, D = {1,....365}. And then there's the issue.

S=365^n

This because the list of future birthdays of n people was its test point; therefore m points will be in the sequence so each point contains 365 distinct outcomes. The probability function P for \Omega is that any event is likely to happen in 365 days.

P(x)=\frac{1}{365^{n}}

if x is between 1 and 365 as well as the occurrence is just all similarly possible

In point i:

That somebody mentions their birthday throughout the party

Guess I was born on day b. Therefore the consequence of "x is in A" is "b is now in the series of x," which is to say, b = bk for some amount k approximately 1 and n.

In point ii:

Any 2 persons share the same birthday at this party". A result x is in B" means which "two of entries in x are same." This means that perhaps the outcome x is in B if or only if bj = bk is in B of two numbers j, and k of 1, of two. , no, n.

In point iii:

Many three students share the same birthday with both the party. The consequence is x at the level of C only when bj = bk = bl at three (different) indices, j, k, l, 1. , no, n.

6 0
2 years ago
The two angles shown in the figure are complementary. What is the value of y?
Free_Kalibri [48]

Complementary angles, sum = 90

So 3y - 4 + 73 = 90

3y + 69 = 90

3y = 21

y = 7

Answer

y = 7

8 0
3 years ago
Read 2 more answers
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