Answer:
B) (-10, -6) and (8, -6)
Step-by-step explanation:
Answer:
7.5 ft³/min
Step-by-step explanation:
Let x be the depth below the surface of the water. The height, h of the water is thus h = 10 - x.
Now, the volume of water V = Ah where A = area of isosceles base of trough = 1/2bh' where b = base of triangle = 4 ft and h' = height of triangle = 1 ft. So, A = 1/2 × 4 ft × 1 ft = 2 ft²
So, V = Ah = 2h = 2(10 - x)
The rate of change of volume is thus
dV/dt = d[2(10 - x)]/dt = -2dx/dt
Since dV/dt = 15 ft³/min,
dx/dt = -(dV/dt)/2 = -15 ft³/min ÷ 2 = -7.5 ft³/min
Since the height of the water is h = 10 - x, the rate at which the water level is rising is dh/dt = d[10 - x]/dt
= -dx/dt
= -(-7.5 ft³/min)
= 7.5 ft³/min
And the height at this point when x = 8 inches = 8 in × 1 ft/12 in = 0.67 ft is h = (10 - 0.67) ft = 9.33 ft
Answer:
5.8 is bigger
Step-by-step explanation:
Answer:
Test statistic = -2.44
There is enough evidence to support the strategist's claim.
Step-by-step explanation:
H0 : p = 0.41
H1 : p < 0.41
pˆ = 0.38
Test statistic :
z=pˆ−p/√p(1−p)/n
Z = (0.38 - 0.41) / √(0.41(1 - 0.41) / 1600
Z = - 0.03 / √0.0001511875
Z = - 0.03 / 0.0122958
Z = - 2.4399
Test statistic = -2.44
The Pvalue :
P(Z < -2.44) = 0.0073436
α - level = 0.02
If Pvalue < α ; Reject H0
0.0073436 < 0.02 ; We reject H0
Since Pvalue < α ; Hence, There is enough evidence to support the strategist's claim.
Answer: c.50 is the answer
