Question

A floor whose length and width is 50 m and 40 m respectively needs to be covered by rectangular tiles. The dimension of each tile is 1 m x 2 m. Find the total number of tiles that would be required to fully cover the floor.
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Answer 1

Answer:

1000

Step-by-step explanation:

area of rectangle = width x length

Given:

• width of floor = 40 m
• length of floor = 50 m

⇒ area of floor = 40 x 50 = 2000 m²

Given:

• width of tile = 1 m
• length of tile = 2 m

⇒ area of tile = 1 x 2 = 2 m²

Number of tiles needed = area of floor ÷ area of one tile

                                       = 2000 ÷ 2

                                       = 1000

Answer 2

Answer:

1000 tiles needed.

area of floor:

• length * width

• 50 * 40

• 2000 m²

area of each tile:

• length * width

• 1 * 2

• 2 m²

solve:

$\sf total \ number \ of \ tiles \ needed = \dfrac{area \ of \ floor}{area \ of \ each \ tile}$

$\sf total \ number \ of \ tiles \ needed = \dfrac{2000}2}$

$\sf total \ number \ of \ tiles \ needed = 1000$