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timama [110]
2 years ago
6

he cost for producing a certain product is $37 each. The fixed costs are $70,000. The selling price for each product is $72. 1.

What is the revenue function? a. R(x) = 37x – 70,000 b. R(x) = 37x c. R(x) = 72x + 70,000 d. R(x) = 72x – 70,000 e. R(x) = 72x 2. What is the profit function? a. P(x) = 72x – 70,000 b. P(x) = 35x – 70,000 c. P(x) = 37x + 70,000 d. P(x) = 35x + 70,000 e. P(x) = 72x + 70,000 . 3. What is the break-even quantity? a. 2,500 b. 4,800 c. 1,846 d. 2,000 e. 4,500 4. What is the break-even point
Business
1 answer:
DIA [1.3K]2 years ago
5 0

Answer:

Instructions are listed below

Explanation:

Giving the following information:

The Variable unitary cost= $37 each.

The fixed costs are $70,000.

The selling price for each product is $72.

1) revenue function= P*X

Revenue function= 72*x

Option E

2) Profit function= (P-Vc)*X-Fc

Profit function= 35*x-70000

Option B

3) break-even quantity= fixed costs/contribution margin

break-even quantity= 70000/35= 2000 units

Option D

4)  break-even point ($)=fixed costs/contribution margin ratio

Contribution margin ratio= contribution margin/P= 0,49

break-even point ($)=70000/0,4861111= $144000

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4 0
1 year ago
A man has $245,000 invested in three properties. One earns 12%, one 10% and one 8%. His annual income from the properties is $23
astraxan [27]

Answer:

for 8% investment = $110000

for 12% investment = $55000

for 10% investment =  $80000

annual income for each property is

x amount for 8% investment = $8800

y amount for 12% investment = $6600

z amount for 10% investment = $8000

Explanation:

Given data

investment = $245000

rate 1 = 12%

rate 2 = 10%

rate 3 = 8%

annual income = $23400

rate = 8%  twice that invested at 12%

to find out

invested in each property and  the annual income from each property

solution

let us consider x amount for 8% investment

and consider y amount for 12% investment

and consider z amount for 10% investment

from question we say,  8% is twice that invested at 12%

x = 2y      ........1

and

x + y + z = 245000      .............2

put 1 in equation 2

2y + y + z = 245000  

z = 245000 - 3y            ...................3

and we can say that

0.08x + 0.12y + 0.10z = 23400              ...........................4

put equation 1 and 3 in 4

0.08(2y) + 0.12y + 0.10( 245000 - 3y ) = 23400

0.16y + 0.12y - 0.3y = -1100

0.02y = 1100

y = $55000

so x = 2(y) = 2(5500) = $110000

and z = 245000 - 3(55000) = $80000

so annual income for each property is

x amount for 8% investment = 0.08 × 110000 = $8800

y amount for 12% investment = 0.12 × 55000 = $6600

z amount for 10% investment = 0.10 × 80000 = $8000

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Answer:

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Answer:

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